I am stumped. I have a data set with multiple columns and about 65,000 case.
Some of the cases have a "#NULL!" value so for dataframe
"Props_":
access_emp pct_vacant TAVAIL park PARKACRES totlandare
4538 52.15 #NULL! 0 1 22.99 74,129.70400
4539 52.15 .09 0 1 22.99 982,850.80400
10292 54.20 #NULL! 1 0 0.00 212,382.82400
11235 52.93 #NULL! 1 1 15.57 1,355,691.04700
14294 55.42 .09 0 0 0.00 36,693.81700
14295 55.42 #NULL! 0 0 0.00 97,526.17400
14296 55.42 #NULL! 0 0 0.00 125,131.20300
14297 55.42 #NULL! 0 0 0.00 209,691.18400
14298 55.42 .09 0 0 0.00 #NULL!
14299 55.42 #NULL! 0 0 0.00 26,161.29100
So i need to replace the the #NULL! with 0. I have tried:
Props_pct_vacant<-Props_pct_vacant[Props_$pct_vacant !="#NULL!"]
Which seems to be deleting the #Null! cases but then the vectors are of
different lengths and i think it casues problems. Ideally i would load the
data and remove all the cases with #NULL! values no matter what column there
in or at least specify the column. So question one is since the NULL value
is actually a "#NULL!" value do the same commands apply becuase it
seems
like they dont work. The main question is how can i remove the #NULL! value
from each of the columns (entire cases is fine) or specified columns.
Thanks in advance.
Josh
--
View this message in context:
http://www.nabble.com/Replacing-null-values-%28-NULL%21%29-tp24540921p24540921.html
Sent from the R help mailing list archive at Nabble.com.