Interesting. Now the fifth homework question you have posted here. As was stated
before (by several members) this is not a homework forum.
Patrick
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
On Behalf Of mathallan
Sent: Friday, May 08, 2009 5:50 AM
To: r-help at r-project.org
Subject: [R] glm fit
Hi, I try to ask here, because I hope someone will help me understand this
problem-
I have fittet a glm in R with the results
> glm1 <-
>
glm(log(claims)~log(sum)*as.factor(grp),family=gaussian(link="identity"))
> summary(glm1)
Call:
glm(formula = log(claims) ~ log(sum) * as.factor(grp), family gaussian(link =
"identity"))
Deviance Residuals:
Min 1Q Median 3Q Max
-6.6836 -1.3626 -0.2576 1.2038 8.2480
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 3.525657 0.436102 8.084 8.18e-16 ***
log(sum) 0.334288 0.025668 13.024 < 2e-16 ***
as.factor(grp)2 0.434262 0.976240 0.445 0.6565
as.factor(grp)3 3.666490 1.436471 2.552 0.0107 *
as.factor(grp)4 0.040782 1.024730 0.040 0.9683
log(sum):as.factor(grp)2 0.007719 0.061914 0.125 0.9008
log(sum):as.factor(grp)3 -0.209986 0.091578 -2.293 0.0219 *
log(sum):as.factor(grp)4 0.059342 0.067320 0.881 0.3781
---
Signif. codes: 0 ?***? 0.001 ?**? 0.01 ?*? 0.05 ?.? 0.1 ? ? 1
(Dispersion parameter for gaussian family taken to be 3.693731)
Null deviance: 15839 on 4035 degrees of freedom
Residual deviance: 14878 on 4028 degrees of freedom
AIC: 16737
Number of Fisher Scoring iterations: 2
But i'm not sure what I get out of the summary. What does it tell me?
How should the formula for Y look like, out from the summary? Is it
something like
Y=0.334288*X_sum+0.434262*X_2+ ??
And when I get a expression for Y, what does it tell me? Is it an expected
expression?
Can anyone help me please?
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