stephen sefick
2009-Jan-07 15:36 UTC
[R] Replace Function (How to replace numbers in a data frame with a specific number)
taxa <- (structure(list(Date = structure(c(4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L), .Label =
c("2006/04",
"2006/05", "2006/07", "2006/10",
"2006/12", "2007/02", "2007/04",
"2007/06", "2007/08", "2007/10",
"2007/12", "2008/01"), class = "factor"),
RiverMile = c(61L, 119L, 148L, 179L, 185L, 187L, 190L, 196L,
198L, 202L, 215L, 61L, 119L, 148L, 179L, 185L, 187L, 190L,
196L, 198L), Site = structure(c(9L, 1L, 2L, 3L, 4L, 10L,
5L, 11L, 6L, 7L, 8L, 9L, 1L, 2L, 3L, 4L, 10L, 5L, 11L, 6L
), .Label = c("119", "148", "179",
"185", "190", "198", "202",
"215", "61", "BC", "HC",
"SC"), class = "factor"), location structure(c(2L,
2L, 2L, 2L, 2L, 1L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
1L, 2L, 1L, 2L), .Label = c("creek", "river"), class =
"factor"),
Amphipoda = c(0, 0, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 0, 0, 1,
0, 1, 1, 0, 1), Coleoptera = c(1, 1, 4, 1, 0, 1, 1, 2, 1,
2, 0, 0, 0, 1, 1, 0, 0, 0, 2, 1), Decapoda = c(0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1), Diptera = c(6,
6, 14, 3, 16, 10, 12, 0, 3, 9, 6, 5, 3, 10, 0, 9, 3, 11,
2, 8), Ephemeroptera = c(5, 6, 4, 1, 3, 1, 3, 1, 0, 2, 0,
2, 2, 2, 0, 0, 0, 0, 1, 0)), .Names = c("Date",
"RiverMile",
"Site", "location", "Amphipoda",
"Coleoptera", "Decapoda", "Diptera",
"Ephemeroptera"), row.names = c("61 2006/10", "119
2006/10",
"148 2006/10", "179 2006/10", "185 2006/10",
"BC 2006/10", "190 2006/10",
"HC 2006/10", "198 2006/10", "202 2006/10",
"215 2006/10", "61 2006/12",
"119 2006/12", "148 2006/12", "179 2006/12",
"185 2006/12", "BC 2006/12",
"190 2006/12", "HC 2006/12", "198 2006/12"), class
= c("cast_df",
"data.frame")))
replace(taxa, taxa>0, 1)
#Is preforms as I would like except that I only want to do this on
columns 5:19 and I can't just use
replace(taxa, taxa[,5:19]>0, 1)
#any suggestions
Stephen Sefick
--
Stephen Sefick
Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us feel like gods. We are mammals, and have not exhausted the
annoying little problems of being mammals.
-K. Mullis
Henrique Dallazuanna
2009-Jan-07 16:18 UTC
[R] Replace Function (How to replace numbers in a data frame with a specific number)
Try this: taxa[, 5:9][taxa[,5:9] > 0] <- 1 On Wed, Jan 7, 2009 at 1:36 PM, stephen sefick <ssefick@gmail.com> wrote:> taxa <- (structure(list(Date = structure(c(4L, 4L, 4L, 4L, 4L, 4L, 4L, > 4L, 4L, 4L, 4L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L), .Label = c("2006/04", > "2006/05", "2006/07", "2006/10", "2006/12", "2007/02", "2007/04", > "2007/06", "2007/08", "2007/10", "2007/12", "2008/01"), class = "factor"), > RiverMile = c(61L, 119L, 148L, 179L, 185L, 187L, 190L, 196L, > 198L, 202L, 215L, 61L, 119L, 148L, 179L, 185L, 187L, 190L, > 196L, 198L), Site = structure(c(9L, 1L, 2L, 3L, 4L, 10L, > 5L, 11L, 6L, 7L, 8L, 9L, 1L, 2L, 3L, 4L, 10L, 5L, 11L, 6L > ), .Label = c("119", "148", "179", "185", "190", "198", "202", > "215", "61", "BC", "HC", "SC"), class = "factor"), location > structure(c(2L, > 2L, 2L, 2L, 2L, 1L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, > 1L, 2L, 1L, 2L), .Label = c("creek", "river"), class = "factor"), > Amphipoda = c(0, 0, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 0, 0, 1, > 0, 1, 1, 0, 1), Coleoptera = c(1, 1, 4, 1, 0, 1, 1, 2, 1, > 2, 0, 0, 0, 1, 1, 0, 0, 0, 2, 1), Decapoda = c(0, 0, 0, 0, > 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1), Diptera = c(6, > 6, 14, 3, 16, 10, 12, 0, 3, 9, 6, 5, 3, 10, 0, 9, 3, 11, > 2, 8), Ephemeroptera = c(5, 6, 4, 1, 3, 1, 3, 1, 0, 2, 0, > 2, 2, 2, 0, 0, 0, 0, 1, 0)), .Names = c("Date", "RiverMile", > "Site", "location", "Amphipoda", "Coleoptera", "Decapoda", "Diptera", > "Ephemeroptera"), row.names = c("61 2006/10", "119 2006/10", > "148 2006/10", "179 2006/10", "185 2006/10", "BC 2006/10", "190 2006/10", > "HC 2006/10", "198 2006/10", "202 2006/10", "215 2006/10", "61 2006/12", > "119 2006/12", "148 2006/12", "179 2006/12", "185 2006/12", "BC 2006/12", > "190 2006/12", "HC 2006/12", "198 2006/12"), class = c("cast_df", > "data.frame"))) > > replace(taxa, taxa>0, 1) > > #Is preforms as I would like except that I only want to do this on > columns 5:19 and I can't just use > > replace(taxa, taxa[,5:19]>0, 1) > > #any suggestions > > Stephen Sefick > > -- > Stephen Sefick > > Let's not spend our time and resources thinking about things that are > so little or so large that all they really do for us is puff us up and > make us feel like gods. We are mammals, and have not exhausted the > annoying little problems of being mammals. > > -K. Mullis > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
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