R help - Dec 2008 - chron - when seconds data not included

I have date and time data which looks like this:

      [,1]     [,2]   
 [1,] "7/1/08" "9:19" 
 [2,] "7/1/08" "9:58" 
 [3,] "7/7/08" "15:47"
 [4,] "7/8/08" "10:03"
 [5,] "7/8/08" "10:32"
 [6,] "7/8/08" "15:22"
 [7,] "7/8/08" "15:27"
 [8,] "7/8/08" "15:40"
 [9,] "7/9/08" "10:25"
[10,] "7/9/08" "10:27"

I would like to use chron on it, so that I can calculate intervals in time.

I can't seem to get chron to accept the time format that doesn't include
seconds.  Do I have to go through and append :00 on every line in order to
use chron?
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On Mon, Dec 8, 2008 at 11:52 PM, Tubin <sredmonson at yahoo.com>
wrote:
>
> I have date and time data which looks like this:
>
>      [,1]     [,2]
>  [1,] "7/1/08" "9:19"
>  [2,] "7/1/08" "9:58"
>  [3,] "7/7/08" "15:47"
>  [4,] "7/8/08" "10:03"
>  [5,] "7/8/08" "10:32"
>  [6,] "7/8/08" "15:22"
>  [7,] "7/8/08" "15:27"
>  [8,] "7/8/08" "15:40"
>  [9,] "7/9/08" "10:25"
> [10,] "7/9/08" "10:27"
>
> I would like to use chron on it, so that I can calculate intervals in time.
>
> I can't seem to get chron to accept the time format that doesn't
include
> seconds.  Do I have to go through and append :00 on every line in order to
> use chron?


That's one way:

m <- matrix( c("7/1/08","9:19",
  "7/1/08","9:58",
  "7/7/08","15:47",
  "7/8/08","10:03",
  "7/8/08","10:32",
  "7/8/08","15:22",
  "7/8/08","15:27",
  "7/8/08","15:40",
  "7/9/08","10:25",
  "7/9/08","10:27"), nc = 2, byrow = TRUE)

chron(m[,1], paste(m[,2], 0, sep = ":"))

# another is to use as.chron

as.chron(apply(m, 1, paste, collapse = " "), "%m/%d/%y
%H:%M")