R help - Oct 2008 - passing a list where names arguments are expected

hi,

say i have a function f and i'd like to to call it like this:

1) f(list(a=...,b=...))

but i can't do it, because f is defined as:

2) f<-function(a=NULL,b=NULL){...}

is there a way that i can approximate 1), such as mapping list(a=,...b=...)
to "list(a=,...b=...)" and then replacing "list" by
"f", and then evaluating
the expression?

thanks.

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I believe you want

do.call(f, list(a =..., b=...))

?do.call
-Kaom
On Oct 19, 2008, at 7:55 PM, erwann rogard wrote:
> hi,
>
> say i have a function f and i'd like to to call it like this:
>
> 1) f(list(a=...,b=...))
>
> but i can't do it, because f is defined as:
>
> 2) f<-function(a=NULL,b=NULL){...}
>
> is there a way that i can approximate 1), such as mapping  
> list(a=,...b=...)
> to "list(a=,...b=...)" and then replacing "list" by
"f", and then
> evaluating
> the expression?
>
> thanks.
>
> 	[[alternative HTML version deleted]]
>
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