R help - Oct 2008 - Running source() on a file in another directory

Suppose I have a file prog.R stored in a directory under ~/dirname,
and ~/dirname is set in a shell script file (e.g. .cshrc) as one of
the accessible paths on terminal. On a different directory I could run
prog.R interactively by executing

source("~/dirname/prog.R")

It seems that source() does not search for all the paths set in the
shell script. So, is there a better and more elegant way to do this,
for example without explicitly typing the directory?

TIA,
Gang

Suppose p is a vector of paths, e.g., p <- c("~/dir1",
"~/dir2/dir3")
Then the following will return the full pathname of the first found
location:

   Find(file.exists, file.path(p, "prog.R"))

so you can source that.

On Wed, Oct 1, 2008 at 6:09 PM, Gang Chen <gangchen6 at gmail.com>
wrote:
> Suppose I have a file prog.R stored in a directory under ~/dirname,
> and ~/dirname is set in a shell script file (e.g. .cshrc) as one of
> the accessible paths on terminal. On a different directory I could run
> prog.R interactively by executing
>
> source("~/dirname/prog.R")
>
> It seems that source() does not search for all the paths set in the
> shell script. So, is there a better and more elegant way to do this,
> for example without explicitly typing the directory?
>
> TIA,
> Gang
>
> ______________________________________________
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> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

Thanks a lot! It seems to work fine now with what you suggested. I
also tried another approach by running the following on the terminal

R -f ~dir1/prog.R

and it read in some lines in prog.R, but then the execution halted at
one point for some reason I could not figure out. Any way I could get
"R -f ..." working?

Thanks,
Gang


On Wed, Oct 1, 2008 at 11:49 PM, Gabor Grothendieck
<ggrothendieck at gmail.com> wrote:
> Suppose p is a vector of paths, e.g., p <- c("~/dir1",
"~/dir2/dir3")
> Then the following will return the full pathname of the first found
> location:
>
>   Find(file.exists, file.path(p, "prog.R"))
>
> so you can source that.
>
> On Wed, Oct 1, 2008 at 6:09 PM, Gang Chen <gangchen6 at gmail.com>
wrote:
>> Suppose I have a file prog.R stored in a directory under ~/dirname,
>> and ~/dirname is set in a shell script file (e.g. .cshrc) as one of
>> the accessible paths on terminal. On a different directory I could run
>> prog.R interactively by executing
>>
>> source("~/dirname/prog.R")
>>
>> It seems that source() does not search for all the paths set in the
>> shell script. So, is there a better and more elegant way to do this,
>> for example without explicitly typing the directory?
>>
>> TIA,
>> Gang