Your IF statement (if (x >= 3:6)) does not work as you probably expect
it since it does not test for the range. You probably want to use
"cut" to convert a value to a bucket in a range:
> x <- 3.5
> cut(x, breaks=seq(-3,5,.2), labels=FALSE)
[1] 33> seq(-3,5,.2)
[1] -3.0 -2.8 -2.6 -2.4 -2.2 -2.0 -1.8 -1.6 -1.4 -1.2 -1.0 -0.8 -0.6
-0.4 -0.2 0.0 0.2
[18] 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 2.4 2.6 2.8
3.0 3.2 3.4 3.6
[35] 3.8 4.0 4.2 4.4 4.6 4.8 5.0> # it is in the 33rd group
>
On Thu, Sep 4, 2008 at 1:52 PM, PDXRugger <J_R_36 at hotmail.com>
wrote:>
> I am trying to lookup a value in 1 of 10 loaded two column-data sets (Bins)
> by displaying the value of the second column based on the value of the
> first. For instance in
>
> Bin1_Acres Bin1_parprob Bin1_TAZ
> [1,] 0.000442 0.9999978 356
> [2,] 0.000453 0.9999954 356
> [3,] 0.000583 0.9999925 366
> [4,] 0.000635 0.9999893 403
> [5,] 0.000756 0.9999854 358
> [6,] 0.000774 0.9999815 530
> [7,] 0.000813 0.9999773 405
> [8,] 0.000970 0.9999724 576
> [9,] 0.001022 0.9999672 569
> [10,] 0.001066 0.9999618 620
>
> I would like to display the column value on Bin1_parprob based on the
> closest match to Bin1_acres. So if the value i am referenceing in column 1
> (Bin1_Acres) is .009999 the value outputted would be .9999672. I keep
> getting a numeric(0) error with the code i am using(see below). I think
the
> issue is i usually dont have an exact match and i am using a >= sign
which
> may be causing the problem. I need the closest match and it needs to be
> larger, not smaller if not exact match is found( which is very common).
>
> #Test value for Vacant acres in TAZ
> TAZDetermine = 24
>
> #Test value for and development size
> Dev_Size= 3.5
>
> #Determines Bin number based on vacant acres in TAZ
> BinSize=function(Dev_Size,BinNumer){
> if (TAZDetermine<=3.999)
> BinNumber=1
> if (TAZDetermine>=4:6.999)
> (BinNumber=2)
> if (TAZDetermine >=10:16.999)
> (BinNumber=3)
> if (TAZDetermine>=17:27.999)
> (BinNumber=4)
> if (TAZDetermine>=28:49.999)
> (BinNumber=5)
> if (TAZDetermine>=50:90.999)
> (BinNumber=6)
> if (TAZDetermine>=91:150.999)
> (BinNumber=7)
> if (TAZDetermine>=151:340.999)
> (BinNumber=8)
> if (TAZDetermine>=341:650.999)
> (BinNumber=9)
> if (TAZDetermine>=651:3000)
> (BinNumber=10)
> BinNumber
> }
>
> #so in this case Bin 4 is selected
>
> #Based on previously selected bin, display second column
> value(Bin1_parprob). Selected value in column 1 may be slightly larger but
> closest match is desirable.
>
> if (BinNumber==1)
> (Loc_Prop=Bin1Main.data[Bin1Main.data$Bin1_Acres >=Dev_Size,1])
> if (BinNumber==2)
> (Loc_Prop=Bin2Main.data[Bin2Main.data$Bin2_Acres>=Dev_Size,1])
> if (BinNumber==3)
> (Loc_Prop=Bin3Main.data[Bin3Main.data$Bin3_Acres>=Dev_Size,1])
> if (BinNumber==4)
> (Loc_Prop=Bin4Main.data[Bin4Main.data$Bin4_Acres>=Dev_Size,1])
> if (BinNumber==5)
> (Loc_Prop=Bin5Main.data[Bin5Main.data$Bin5_Acres>=Dev_Size,1])
> if (BinNumber==6)
> (Loc_Prop=Bin6Main.data[Bin6Main.data$Bin6_Acres>=Dev_Size,1])
> if (BinNumber==7)
> (Loc_Prop=Bin7Main.data[Bin7Main.data$Bin7_Acres>=Dev_Size,1])
> if (BinNumber==8)
> (Loc_Prop=Bin8Main.data[Bin8Main.data$Bin8_Acres>=Dev_Size,1])
> if (BinNumber==9)
> (Loc_Prop=Bin9Main.data[Bin9Main.data$Bin9_Acres>=Dev_Size,1])
> if (BinNumber==10)
> (Loc_Prop=Bin10Main.data[Bin10Main.data$Bin10_Acres>=Dev_Size,1])
>
> I hope this question is clear. I have tried a number of different lines of
> code but get the same error (Numeric (0))
> Cheers,
> JR
> --
> View this message in context:
http://www.nabble.com/Error-in-table-lookup-tp19316307p19316307.html
> Sent from the R help mailing list archive at Nabble.com.
>
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>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?