Hi there, I hope this question is not as stupid as the one before ... I tried to shorten my histogram (because the distribution is quite skewed and I simply don't want to see the long tail but still use the histogram plot). How can I do something like this? (The example does not work but I don't know why...) data <- rnorm(100) # as example, of course this is not skewed... h <- hist(data, plot=FALSE) mh <- 5 hh <- list(h$breaks[0:(mh+1)], h$counts[0:mh],h$intensities[0:mh],h$density[0:mh],h$mids[0:mh],h$xname,h$equidist) names(hh) <- names(h) plot(hh) Antje
Antje, Have a look at ?hist. It seems like you want this: data <- rnorm(100) hist(data, xlim = c(0,6)) HTH, Thierry ------------------------------------------------------------------------ ---- ir. Thierry Onkelinx Instituut voor natuur- en bosonderzoek / Research Institute for Nature and Forest Cel biometrie, methodologie en kwaliteitszorg / Section biometrics, methodology and quality assurance Gaverstraat 4 9500 Geraardsbergen Belgium tel. + 32 54/436 185 Thierry.Onkelinx op inbo.be www.inbo.be To call in the statistician after the experiment is done may be no more than asking him to perform a post-mortem examination: he may be able to say what the experiment died of. ~ Sir Ronald Aylmer Fisher The plural of anecdote is not data. ~ Roger Brinner The combination of some data and an aching desire for an answer does not ensure that a reasonable answer can be extracted from a given body of data. ~ John Tukey -----Oorspronkelijk bericht----- Van: r-help-bounces op r-project.org [mailto:r-help-bounces op r-project.org] Namens Antje Verzonden: maandag 1 september 2008 15:44 Aan: r-help op stat.math.ethz.ch Onderwerp: [R] another histogram question Hi there, I hope this question is not as stupid as the one before ... I tried to shorten my histogram (because the distribution is quite skewed and I simply don't want to see the long tail but still use the histogram plot). How can I do something like this? (The example does not work but I don't know why...) data <- rnorm(100) # as example, of course this is not skewed... h <- hist(data, plot=FALSE) mh <- 5 hh <- list(h$breaks[0:(mh+1)], h$counts[0:mh],h$intensities[0:mh],h$density[0:mh],h$mids[0:mh],h$xname, h$equidist) names(hh) <- names(h) plot(hh) Antje ______________________________________________ R-help op r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Dit bericht en eventuele bijlagen geven enkel de visie van de schrijver weer en binden het INBO onder geen enkel beding, zolang dit bericht niet bevestigd is door een geldig ondertekend document. The views expressed in this message and any annex are purely those of the writer and may not be regarded as stating an official position of INBO, as long as the message is not confirmed by a duly signed document
You can do this: hh <- lapply(h, head, mh) hh$breaks <- head(h$breaks, mh + 1) class(hh) <- "histogram" plot(hh) On Mon, Sep 1, 2008 at 10:44 AM, Antje <niederlein-rstat@yahoo.de> wrote:> Hi there, > > I hope this question is not as stupid as the one before ... > I tried to shorten my histogram (because the distribution is quite skewed > and I simply don't want to see the long tail but still use the histogram > plot). How can I do something like this? (The example does not work but I > don't know why...) > > data <- rnorm(100) # as example, of course this is not skewed... > > h <- hist(data, plot=FALSE) > mh <- 5 > hh <- list(h$breaks[0:(mh+1)], > h$counts[0:mh],h$intensities[0:mh],h$density[0:mh],h$mids[0:mh],h$xname,h$equidist) > names(hh) <- names(h) > plot(hh) > > > Antje > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
> I tried to shorten my histogram (because the distribution is quite skewed > and I simply don't want to see the long tail but still use the histogram > plot). How can I do something like this? (The example does not work but I > don't know why...) > > data <- rnorm(100) # as example, of course this is not skewed...Hmm not sure if this is what you want, but maybe subset the data: hist(data[data > -1]) m.> > h <- hist(data, plot=FALSE) > mh <- 5 > hh <- list(h$breaks[0:(mh+1)], > h$counts[0:mh],h$intensities[0:mh],h$density[0:mh],h$mids[0:mh],h$xname,h$equidist) > names(hh) <- names(h) > plot(hh) > > > Antje > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Marianne Promberger Graduate student in Psychology http://www.psych.upenn.edu/~mpromber