R help - Aug 2008 - use expression() in a loop

Hi all,

I want to do plot() in a loop to make 10 graphs, so I have some code like

for (i in 1:10) {
   plot(... ... , xlab = expression(g[i]) )
}

I expect g_1, g_2, and so on appear on x labels, but it simply prints
g_i for each graph. Does anybody know how to get around this problem?
Thanks.

NL

Nanye Long said the following on 8/18/2008 3:00 PM:
> Hi all,
> 
> I want to do plot() in a loop to make 10 graphs, so I have some code like
> 
> for (i in 1:10) {
>    plot(... ... , xlab = expression(g[i]) )
> }
> 
> I expect g_1, g_2, and so on appear on x labels, but it simply prints
> g_i for each graph. Does anybody know how to get around this problem?
> Thanks.
> 
> NL
> 
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
Try:

par(mfrow = c(2, 5))
for (i in 1:10) {
   plot(1, 1, xlab = bquote(g[.(i)]))
}

HTH,

--sundar

on 08/18/2008 05:00 PM Nanye Long wrote:
> Hi all,
> 
> I want to do plot() in a loop to make 10 graphs, so I have some code like
> 
> for (i in 1:10) {
>    plot(... ... , xlab = expression(g[i]) )
> }
> 
> I expect g_1, g_2, and so on appear on x labels, but it simply prints
> g_i for each graph. Does anybody know how to get around this problem?
> Thanks.
> 
> NL
Try this:

par(mfrow = c(5, 2))

for (i in 1:10)
  plot(1, xlab = bquote(g[.(i)]))


Note the use of bquote() and the use of .(i), which replaces 'i' with
the value of i in each iteration.

See ?plotmath for some examples and ?bquote

HTH,

Marc Schwartz