R help - Jul 2008 - how to capture matching words in a string ?

I need to capture matching words in a string, any ideas ?
 
I tried using gregexpr, but it was no help. In this example, I need to capture
ID23423424 and ID324234325
 
> s <- "sID23423424 apple pID324234325 orange">
gregexpr("ID[0-9]+", s)[[1]][1]  2
20attr(,"match.length")[1] 10 11
 
 
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Try this and see the gsubfn home page for more info:
http://gsubfn.googlecode.com
> library(gsubfn)
Loading required package: proto
>
> s <- "sID23423424 apple pID324234325 orange"
> strapply(s, "ID[0-9]+")[[1]]
[1] "ID23423424"  "ID324234325"


On Wed, Jul 2, 2008 at 9:33 PM, Daren Tan <daren76 at hotmail.com>
wrote:
>
> I need to capture matching words in a string, any ideas ?
>
> I tried using gregexpr, but it was no help. In this example, I need to
capture ID23423424 and ID324234325
>
>> s <- "sID23423424 apple pID324234325 orange">
gregexpr("ID[0-9]+", s)[[1]][1]  2
20attr(,"match.length")[1] 10 11
>
>
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