Xin
2007-Dec-14 09:09 UTC
[R] can I solve this equation in R----29.040x+1=327.727x^(355.768x/(1-x))
-29.040x+1=327.727x^(355.768x/(1-x)) [[alternative HTML version deleted]]
Uwe Ligges
2007-Dec-14 09:49 UTC
[R] can I solve this equation in R----29.040x+1=327.727x^(355.768x/(1-x))
Well, numerically by re-writing -29.040x+1 = 327.727x^(355.768x/(1-x)) 0 = 327.727x^(355.768x/(1-x)) - (-29.040x+1) 0^2 = (327.727x^(355.768x/(1-x)) - (-29.040x+1))^2 and then minimizing the right hand side: optimize(function(x) (327.727 * x^(355.768*x / (1-x)) - (-29.040*x + 1))^2, interval = c(0, 1)) Uwe Ligges Xin wrote:> -29.040x+1=327.727x^(355.768x/(1-x)) > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.