Here is one way of doing it:
> x
[,1] [,2] [,3]
[1,] 2 4 6
[2,] 1 2 NA
[3,] 4 6 NA> y
[,1] [,2] [,3]
[1,] NA 4 4
[2,] 2 2 NA
[3,] 1 2 2> z <- mapply(function(a,b)mean(c(a,b), na.rm=TRUE), x, y)
> dim(z) <- dim(x)
> z
[,1] [,2] [,3]
[1,] 2.0 4 5
[2,] 1.5 2 NaN
[3,] 2.5 4 2> # to change it to NA
> is.na(z) <- is.nan(z)
> z
[,1] [,2] [,3]
[1,] 2.0 4 5
[2,] 1.5 2 NA
[3,] 2.5 4 2>
>
On Nov 11, 2007 4:52 PM, affy snp <affysnp at gmail.com>
wrote:> Dear list,
>
> I am new to R and very inexperienced. Sorry for the trouble.
> I have two txt files and want to merge them by taking the average.
> More specifically, for example, the txt file1, with row names and column
names,
> consists of 238000 rows and 196 columns. Each column corresponds
> to a sample. The data is mixed with numeric or NA. So what I plan to
> do is:
>
> (1) Take the 1st column from txt file 1 and txt file 2, calculate the
average
> if both numbers are numeric. If one is numeric and the other one is NA or
> the opposite, just use the numeric; If both are NA, then use NA, Do all
this
> for all columns
> (2) Create txt file 3 with the numbers from the above and add the row names
and
> column names.
>
> So an illustrative example could be:
>
> txt file 1
>
> A B C
> row1 2 4 6
> row2 1 2 NA
> row3 4 6 NA
>
> txt file 2
>
> A B C
> row1 NA 4 4
> row2 2 2 NA
> row3 1 2 2
>
> then txt file 3 will be created as:
>
> A B C
> row1 2 4 5
> row2 1.5 2 NA
> row3 2.5 4 2
>
> Any help will be appreciated.
>
> Thanks!
> Allen
>
> ______________________________________________
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> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?