Hi Montserrat,
What exactly would you like to plot?
Your differential equation can be easily integrated so
that you can get an implicit expression for F(x), i.e.
expression like G(c,x,F(x)) = 0 where G is a known
function and c is an arbitrary constant. For every
value of c and each value of x such that x < (-1/k2 +
(k1+k2)*ln(k1+k2)/k2^2) [if my calculations are
correct!] there exist 2 possible values of F(x): one
with F(x) <1 and one with F(x) > 1. So for each c you
have two branches of the function F defined for x <
x(c). You will need a numerical procedure to find
these two values of F(x).
Regards,
Moshe.
--- Montse Rue <montse.rue at gmail.com> wrote:
> Hi,
>
> I would like to plot the following equation:
>
> dF(x)/dx=(k1+k2F(x))(1-F(x))
>
> where k1 and k2 are parameters that I have estimated
> already.
>
> How can I plot the curve in R?
>
> Thanks!
>
> Montserrat Rue
> Universitat de Lleida (Spain)
>
> [[alternative HTML version deleted]]
>
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