? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile Url: https://stat.ethz.ch/pipermail/r-help/attachments/20070402/46641d2e/attachment.pl
if your data set is a matrix try this
new.data <- cbind(data, "New Column" = is.na(data[,
"Years"]) & data[,
"Products"] > 20)
whereas if your data set is a data.frame try this
data$"New.Column" <- as.numeric(is.na(data$Years) &
data$Products >
20)
I hope it helps.
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
----- Original Message -----
From: "Sergio Della Franca" <sergio.della.franca at gmail.com>
To: <r-help at stat.math.ethz.ch>
Sent: Monday, April 02, 2007 1:31 PM
Subject: [R] substitute values
> Dear R-Helpers,
>
> I have the following data set(y):
>
> Years Products
> 1 10
> 2 25
> 3 40
> 4 NA
> 5 35
> <NA> 23
> 6 NA
> 7 67
> 8 NA
>
> I want to create a new column into my dataset(y) under the following
> conditions:
> if years =NA and products >20 then new column=1 else new column=0;
> to obtain the following results:
>
> Years Products New Column
> 1 10 0
> 2 25 0
> 3 40 0
> 4 NA 0
> 5 35 0
> <NA> 23 1
> 6 NA 0
> 7 67 0
> 8 NA 0
>
> Thank you in advance.
>
>
> Serigo Della Franca
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm
Sergio Della Franca wrote:> Dear R-Helpers, > > I have the following data set(y): > > Years Products > 1 10 > 2 25 > 3 40 > 4 NA > 5 35 > <NA> 23 > 6 NA > 7 67 > 8 NA > > I want to create a new column into my dataset(y) under the following > conditions: > if years =NA and products >20 then new column=1 else new column=0; > to obtain the following results: > > Years Products New Column > 1 10 0 > 2 25 0 > 3 40 0 > 4 NA 0 > 5 35 0 > <NA> 23 1 > 6 NA 0 > 7 67 0 > 8 NA 0 >How about using ifelse(): year = c(1,2,3,4,5,NA,6,7,8) products = c(10,25,40,NA,35,23,NA,67,NA) ifelse(is.na(year) & products>20,1,0) => [1] 0 0 0 0 0 1 0 0 0 Mark -- Dr. Mark Wardle Specialist registrar, Neurology Cardiff, UK