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remko duursma

2007-Mar-13 13:02 UTC

[R] 'substitute' question

# I use this code to label a graph with the R2:

# graph
x <- rnorm(100)
y <- x + rnorm(100)
lm1 <- lm(y~x)
plot(x,y)

# label
R2text <- substitute(paste(R^2," = ",r2),list(r2=r2))
text(1,-3,R2text, col="red")

# i have modified this a bit, so that i have a vector with other labels, 
each of which
# will be labelled on the graph. Example:
texts <- c("And the R2 is", R2text)
x <- c(-2,-2)
y <- c(2,1)
for(i in 1:length(texts))text(x[i],y[i],texts[i],pos=4, col="blue")

# As you can see the label "R2 = 48.7" remains at "paste(R^2,
" = ", 48.7)"
# What to do?



Thanks for your help,

Remko



..-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-
Remko Duursma
Post-doctoral researcher
Dept. Forest Ecology
University of Helsinki, Finland

_________________________________________________________________
With tax season right around the corner, make sure to follow these few 
simple tips.

Stephen Tucker

2007-Mar-13 13:17 UTC

head link

[R] 'substitute' question

hi,

your first argument to substitute should be an expression, not a character
string (which the output of paste() will give you)

so...
# first assign to variable r2 (think you forgot to do that)
# in your example
r2 <- summary(lm1)$r.squared

# then to your label
R2text <- substitute(R^2==r2,list(r2=round(r2,2)))

# then you can annotate with text() as you did

alternatively, you can use 
R2text <- bquote(R^2==.(round(r2,2)))


--- remko duursma <remkoduursma at hotmail.com> wrote:
> 
> # I use this code to label a graph with the R2:
> 
> # graph
> x <- rnorm(100)
> y <- x + rnorm(100)
> lm1 <- lm(y~x)
> plot(x,y)
> 
> # label
> R2text <- substitute(paste(R^2," = ",r2),list(r2=r2))
> text(1,-3,R2text, col="red")
> 
> # i have modified this a bit, so that i have a vector with other labels, 
> each of which
> # will be labelled on the graph. Example:
> texts <- c("And the R2 is", R2text)
> x <- c(-2,-2)
> y <- c(2,1)
> for(i in 1:length(texts))text(x[i],y[i],texts[i],pos=4,
col="blue")
> 
> # As you can see the label "R2 = 48.7" remains at
"paste(R^2, " = ", 48.7)"
> # What to do?
> 
> 
> 
> Thanks for your help,
> 
> Remko
> 
> 
> 
> ..-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-
> Remko Duursma
> Post-doctoral researcher
> Dept. Forest Ecology
> University of Helsinki, Finland
> 
> _________________________________________________________________
> With tax season right around the corner, make sure to follow these few 
> simple tips.
> 
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 


 
____________________________________________________________________________________
Finding fabulous fares is fun.

Mendiburu, Felipe (CIP)

2007-Mar-13 13:26 UTC

head link

[R] 'substitute' question

Dear Renko

To modify the script

plot(x,y)
r2<-summary(lm1)$r.squared*100
# label
R2text <- substitute(paste(R^2," = ",r2),list(r2=r2))
text(-1,1,R2text, col="red") # To see of the coordinates of the graph.

Grettings

Felipe

-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch]On Behalf Of remko duursma
Sent: Tuesday, March 13, 2007 8:02 AM
To: r-help at stat.math.ethz.ch
Subject: [R] 'substitute' question



# I use this code to label a graph with the R2:

# graph
x <- rnorm(100)
y <- x + rnorm(100)
lm1 <- lm(y~x)
plot(x,y)

# label
R2text <- substitute(paste(R^2," = ",r2),list(r2=r2))
text(1,-3,R2text, col="red")

# i have modified this a bit, so that i have a vector with other labels, 
each of which
# will be labelled on the graph. Example:
texts <- c("And the R2 is", R2text)
x <- c(-2,-2)
y <- c(2,1)
for(i in 1:length(texts))text(x[i],y[i],texts[i],pos=4, col="blue")

# As you can see the label "R2 = 48.7" remains at "paste(R^2,
" = ", 48.7)"
# What to do?



Thanks for your help,

Remko



..-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-
Remko Duursma
Post-doctoral researcher
Dept. Forest Ecology
University of Helsinki, Finland

_________________________________________________________________
With tax season right around the corner, make sure to follow these few 
simple tips.

______________________________________________
R-help at stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Bojanowski, M.J. (Michal)

2007-Mar-13 13:40 UTC

head link

[R] 'substitute' question

I do not understand why you play with 'substitute' instead of something
like this:

# CAUTION: this will work only for bivariate case

# plotmaking function
plotModel <- function(m)
{
	x <- m$model$x
	y <- m$model$y
	r2 <- summary(m)$r.squared
	plot(x,y)
	abline(m)
	text( min(x), max(y), paste("And the R^2 is", round(r2,3)),
pos=4)
	invisible(NULL)
}

# your data
x <- rnorm(100)
y <- x + rnorm(100)
lm1 <- lm(y~x)
# make the plot
plotModel(lm1)



*** Note that my e-mail address has changed to m.j.bojanowski at uu.nl
*** Please update your address books accordingly. Thank you!

_________________________________________
Michal Bojanowski
ICS / Sociology
Utrecht University
Heidelberglaan 2; 3584 CS Utrecht
Room 1428
m.j.bojanowski at uu.nl
http://www.fss.uu.nl/soc/bojanowski
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of remko duursma
Sent: Tuesday, March 13, 2007 2:02 PM
To: r-help at stat.math.ethz.ch
Subject: [R] 'substitute' question


# I use this code to label a graph with the R2:

# graph
x <- rnorm(100)
y <- x + rnorm(100)
lm1 <- lm(y~x)
plot(x,y)

# label
R2text <- substitute(paste(R^2," = ",r2),list(r2=r2))
text(1,-3,R2text,
col="red")

# i have modified this a bit, so that i have a vector with other labels,
each of which # will be labelled on the graph. Example:
texts <- c("And the R2 is", R2text)
x <- c(-2,-2)
y <- c(2,1)
for(i in 1:length(texts))text(x[i],y[i],texts[i],pos=4, col="blue")

# As you can see the label "R2 = 48.7" remains at "paste(R^2,
" = ",
48.7)"
# What to do?



Thanks for your help,

Remko



..-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-
Remko Duursma
Post-doctoral researcher
Dept. Forest Ecology
University of Helsinki, Finland

_________________________________________________________________
With tax season right around the corner, make sure to follow these few
simple tips.

______________________________________________
R-help at stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Bojanowski, M.J. (Michal)

2007-Mar-13 14:50 UTC

head link

[R] 'substitute' question

I'm sorry for my first post as I did not properly understood your
problem.
The reason why you were getting "paste(R^2, " = ", 48.7)"
instead of the
properly formatted R^2=48.7
is that in creating 'texts' in your code you were mixing character
string with expressions resulting in 'texts' being a list not a vector.
The only modification to make is to index texts with double square
brackets as below

# the figure
x <- rnorm(100)
y <- x + rnorm(100)
lm1 <- lm(y~x)
plot(x,y)
# label
R2text <- substitute(paste(R^2," = ",r2),list(r2=r2))
text(1,-3,R2text,
col="red")

# i expanded your list of labels to four elements...
texts <- c("And the R2 is", R2text, "third label",
"fourth label")
# texts is a list not an atomic vector
class(texts)
str(texts)

# ... and added more coordinates accordingly
x <- c(-2,-2, -1, -1)
y <- c(2,1, 2, 1)
# here 'texts[[i]]' instead of 'texts[i]'
for(i in 1:length(texts))text(x[i],y[i], texts[[i]],pos=4, col="blue")

hth,
Michal


*** Note that my e-mail address has changed to m.j.bojanowski at uu.nl
*** Please update your address books accordingly. Thank you!

_________________________________________
Michal Bojanowski
ICS / Sociology
Utrecht University
Heidelberglaan 2; 3584 CS Utrecht
Room 1428
m.j.bojanowski at uu.nl
http://www.fss.uu.nl/soc/bojanowski
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of remko duursma
Sent: Tuesday, March 13, 2007 2:02 PM
To: r-help at stat.math.ethz.ch
Subject: [R] 'substitute' question


# I use this code to label a graph with the R2:

# graph
x <- rnorm(100)
y <- x + rnorm(100)
lm1 <- lm(y~x)
plot(x,y)

# label
R2text <- substitute(paste(R^2," = ",r2),list(r2=r2))
text(1,-3,R2text,
col="red")

# i have modified this a bit, so that i have a vector with other labels,
each of which # will be labelled on the graph. Example:
texts <- c("And the R2 is", R2text)
x <- c(-2,-2)
y <- c(2,1)
for(i in 1:length(texts))text(x[i],y[i],texts[i],pos=4, col="blue")

# As you can see the label "R2 = 48.7" remains at "paste(R^2,
" = ",
48.7)"
# What to do?



Thanks for your help,

Remko



..-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-
Remko Duursma
Post-doctoral researcher
Dept. Forest Ecology
University of Helsinki, Finland

_________________________________________________________________
With tax season right around the corner, make sure to follow these few
simple tips.

______________________________________________
R-help at stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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