Ethan,
It is quite easy if you use the sample function with replace=TRUE:
> y<-rnorm(9,0,1)
> y
[1] 0.0625366 -0.1225751 0.1335859 -1.5930572 0.2493484 -0.1926270
-0.5615023
[8] 0.7537500 1.4977661> sample(y,replace=TRUE)
[1] 1.4977661 0.1335859 0.0625366 0.2493484 -0.1225751 1.4977661
0.7537500
[8] 0.2493484 0.0625366
John
John Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
Baltimore VA Medical Center GRECC,
University of Maryland School of Medicine Claude D. Pepper OAIC,
University of Maryland Clinical Nutrition Research Unit, and
Baltimore VA Center Stroke of Excellence
University of Maryland School of Medicine
Division of Gerontology
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-1524
(Phone) 410-605-7119
(Fax) 410-605-7913 (Please call phone number above prior to faxing)
jsorkin at grecc.umaryland.edu
>>> "Ethan Johnsons" <ethan.johnsons at gmail.com>
12/10/06 2:27 AM >>>
How do you draw a bootstrap sample of size 9, with replacement, from
the random dataset I drew? Is there a function for it in R?
9 random samples.
>rnorm(9, 0, 1)
[1] 1.2071538 0.3183367 -1.4237989 -0.4050909 0.9953866 0.9588178
0.9180879
[8] -0.1509696 -1.2230688
thx
ej
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