Dear R users,
Do you know of a way to precise an out.format for a chron object that
would use numbers for months and yet 4 digits for the year?
I have tried out.format=c("d-m-year") (note the m instead of either
mon or month) but got 27-Feb-1992.
Also, the help for chron tells us how to define an out.format when we
create a chron object, but how can you change the out.format of an
existing chron object?
Thanks in advance,
Denis
As discussed the Help Desk article in R News 4/1, the 2 vs 4 year
length is controlled by the chron.year.abb option, e.g.
options(chron.year.abb = FALSE)
chron(20)
however, as also discussed there its not really recommended that
you use this option so try this instead:
ddmmyyyy <- function( x )
with( month.day.year( x ), sprintf( "%02.f-%02.f-%04.f", day,
month, year) )
chron( 20, out.format = ddmmyyyy )
On 10/19/06, Denis Chabot <chabotd at globetrotter.net>
wrote:> Dear R users,
>
> Do you know of a way to precise an out.format for a chron object that
> would use numbers for months and yet 4 digits for the year?
>
> I have tried out.format=c("d-m-year") (note the m instead of
either
> mon or month) but got 27-Feb-1992.
>
> Also, the help for chron tells us how to define an out.format when we
> create a chron object, but how can you change the out.format of an
> existing chron object?
>
> Thanks in advance,
>
> Denis
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
For your second question: x <- chron(1) x <- chron(x, out.format = ddmmyyyy) using the ddmmyyyy from below. On 10/19/06, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:> As discussed the Help Desk article in R News 4/1, the 2 vs 4 year > length is controlled by the chron.year.abb option, e.g. > > options(chron.year.abb = FALSE) > chron(20) > > however, as also discussed there its not really recommended that > you use this option so try this instead: > > ddmmyyyy <- function( x ) > with( month.day.year( x ), sprintf( "%02.f-%02.f-%04.f", day, > month, year) ) > chron( 20, out.format = ddmmyyyy ) > > > > > On 10/19/06, Denis Chabot <chabotd at globetrotter.net> wrote: > > Dear R users, > > > > Do you know of a way to precise an out.format for a chron object that > > would use numbers for months and yet 4 digits for the year? > > > > I have tried out.format=c("d-m-year") (note the m instead of either > > mon or month) but got 27-Feb-1992. > > > > Also, the help for chron tells us how to define an out.format when we > > create a chron object, but how can you change the out.format of an > > existing chron object? > > > > Thanks in advance, > > > > Denis > > > > ______________________________________________ > > R-help at stat.math.ethz.ch mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > >
Got it Gabor, Thank you very much. Denis Le 06-10-19 ? 10:38, Gabor Grothendieck a ?crit :> For your second question: > > x <- chron(1) > x <- chron(x, out.format = ddmmyyyy) > > using the ddmmyyyy from below. > > On 10/19/06, Gabor Grothendieck <ggrothendieck at gmail.com> wrote: >> As discussed the Help Desk article in R News 4/1, the 2 vs 4 year >> length is controlled by the chron.year.abb option, e.g. >> >> options(chron.year.abb = FALSE) >> chron(20) >> >> however, as also discussed there its not really recommended that >> you use this option so try this instead: >> >> ddmmyyyy <- function( x ) >> with( month.day.year( x ), sprintf( "%02.f-%02.f-%04.f", day, >> month, year) ) >> chron( 20, out.format = ddmmyyyy ) >> >> >> >> >> On 10/19/06, Denis Chabot <chabotd at globetrotter.net> wrote: >> > Dear R users, >> > >> > Do you know of a way to precise an out.format for a chron object >> that >> > would use numbers for months and yet 4 digits for the year? >> > >> > I have tried out.format=c("d-m-year") (note the m instead of either >> > mon or month) but got 27-Feb-1992. >> > >> > Also, the help for chron tells us how to define an out.format >> when we >> > create a chron object, but how can you change the out.format of an >> > existing chron object? >> > >> > Thanks in advance, >> > >> > Denis >> > >> > ______________________________________________ >> > R-help at stat.math.ethz.ch mailing list >> > https://stat.ethz.ch/mailman/listinfo/r-help >> > PLEASE do read the posting guide http://www.R-project.org/ >> posting-guide.html >> > and provide commented, minimal, self-contained, reproducible code. >> > >>