Try this:
X <- structure(11:15, .Names = letters[1:5])
Y <- structure(21:25, .Names = letters[1:5])
rbind(group1 = X, group2 = Y)
tab <- rbind(group1 = X, group2 = Y)
tab[,-1] / tab[,1]
On 10/17/06, Leeds, Mark (IED) <Mark.Leeds at morganstanley.com>
wrote:> I have two numeric vectors each of length 17 and each is named the exact
> same way.
>
> so
> obsnum ppppp ppppm pppmp . dot dot dot......
> temp1 is 1417 52 63 85
>
> obsnum ppppp ppppm pppmp . dot dot dot......
> temp2 is 1213 41 50 97
>
> what i want to have is a resultant matrix with 2 rows and 16 columns
> where the 16 columns are the 2:17 columns divided by the respective
> first element in each vector.
> ( so 52, 63 and 85 should all get divided by 1417 and 41, 50 and 97
> should all be divided by 1213 ).
>
> it doesn't have to retain the column names because i can just assign
> them again when i am assigning the rownames.
>
> below is my code :
>
> resultmatrix<-rbind(temp1,temp2)
> resultmatrix<-resultmatrix[,2:17]/resultmatrix[,1]
>
> colnames(resultmatrix)<-colnames(temp1)
> rownames(resultmatrix)<-c("group1","group2")
>
> I'm pretty sure above will work but it seemed kind of ugly and I
> wondering if there is a better way because i am trying to improve in R.
> if there isn't, that's fine. thanks.
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