Dear all,
I have a question about merge two character vectors of the same
length into one.
For example:
X= c('A', 'B', 'C', 'A', 'D',
.......) # 26 possible
alphabet values with length 1000
Y=c('B', 'A', 'C', 'A', 'C',
........) # 26 possible
aphabet values with length 1000
after using table ( X,Y ), I will get a matrix of 26*26. But I
want to sort these values from large to small, that is to say, I want
to get an output like this;
AB 75
AC 60
CC 58
....
How can I get this kind of output?
Thank you very much!
--
Zhiqiang Ye
What about this:> X <- c("A", "B", "C", "A", "D", "A") > Y <- c("B", "A", "C", "A", "C", "B")> XY <- paste(X, Y, sep="")> sort(table(XY), decreasing=TRUE)XY AB AA BA CC DC 2 1 1 1 1 On 3/26/06, Zhiqiang Ye <yezhiqiang@gmail.com> wrote:> > Dear all, > > I have a question about merge two character vectors of the same > length into one. > >-- Sarah Goslee http://www.stringpage.com [[alternative HTML version deleted]]
On 3/26/2006 11:26 AM, Zhiqiang Ye wrote:> Dear all, > > I have a question about merge two character vectors of the same > length into one. > > For example: > > X= c('A', 'B', 'C', 'A', 'D', .......) # 26 possible > alphabet values with length 1000 > Y=c('B', 'A', 'C', 'A', 'C', ........) # 26 possible > aphabet values with length 1000 > > after using table ( X,Y ), I will get a matrix of 26*26. But I > want to sort these values from large to small, that is to say, I want > to get an output like this; > > AB 75 > AC 60 > CC 58 > .... > > How can I get this kind of output?I am not sure I understand what you want (e.g. I would have expected to see BA in your list). But you can get the table of pairs via table(paste(X, Y, sep="")) and you can sort it if you want, e.g. > X= c('A', 'B', 'C', 'A', 'D', 'A') > Y= c('B', 'A', 'C', 'A', 'C', 'B') > table(paste(X,Y,sep="")) AA AB BA CC DC 1 2 1 1 1 > sort(table(paste(X,Y,sep="")), dec=TRUE) AB AA BA CC DC 2 1 1 1 1