?apply
as in:
answer<-apply(yourframe,2,function(x)x[EXP==1 & DOSE==1])
Note that there are slicker ways to do this call.
Note also for that for the particular case of column means, you have a
built-in much faster alternative:
answer<-colMeans(yourframe[EXP==1 & DOSE==1,],na.rm=TRUE)
Also note that the == construction may be problematic if EXP or DOSE are not
factors, say.
Finally, you need to start reading the R docs to learn about this yourself.
"An Introduction to R" is a good place to start.
Oh... and your attempt below will certainly not work. After you read the
basic docs, you'll see why not.
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
> -----Original Message-----
> From: r-help-bounces at stat.math.ethz.ch
> [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Kevin Middleton
> Sent: Friday, February 03, 2006 1:41 PM
> To: r-help at stat.math.ethz.ch
> Subject: [R] Using string vectors as for loop arguments
>
> Is there a mechanism to interate through a vector of strings? Say I
> have a data frame of 50 variables (VAR1 to VAR50), each with 100
> measurements along with some coding factors (EXP and DOSE). I
> want to
> calculate the mean of a subset of each of VAR1 to VAR 50 (selecting
> by EXP and DOSE). Rather than just copy/pasting the same code 50
> times, I thought of using a for loop to go through a vector of VAR1
> to VAR50 (VAR.LIST below). Each iteration would be the variable name
> for which the mean would be calculated.
>
> Trying this, I get an error that the argument is not numeric or
> logical. So I assume that for loops with vectors of strings are
> disallowed. What I am wondering is whether there a way to mimic this
> sort of procedure?
>
> The code looked something like this:
>
> VAR.LIST<-paste(c("VAR"), 1:50, sep="")
>
> for (i in VAR.LIST){
> mean(i[EXP==1 & DOSE==1], na.rm=T)
> }
>
>
>
> Thanks
> Kevin Middleton
>
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