Dear statisticians,
I would like to save results for a "for loop" in a vector previously
created.
My result would be of class "matrix".
I tried the following script:
Script:
#Creation of a previous vector
n.Tree<-2
VectorX<-rep(1,n.Tree)
#loop
for (i in 1:2) {
Ti<-MatOccurTree[Tree[i],1] #number of observation for Tree i
Xi<-matrix(data=1,nrow=Ti,ncol=2)
Xi[,2]<-treedata2$lnE[IdentTree==Tree[i]]
VectorX[i]<-Xi
}
Console:> VectorX[i]<-Xi
Warning message:
le nombre d'objets à remplacer n'est pas multiple de la taille du
remplacement
"number of object to replace isn't a multiple of the length of the
replacement"
Would you have any solution to create a vector of matrix "VectorX" ?
Thanks for your help.
Ghislain Vieilledent.
[[alternative HTML version deleted]]
It seems that Xi is a matrix; so it can't be included in a vector.
You need to create a list for the result of your "for" loop.
res <- list()
for ( i in ...) {
res[[i]] <- Xi }
Vieilledent Ghislain a ??crit :
>Dear statisticians,
>
>I would like to save results for a "for loop" in a vector
previously created.
>My result would be of class "matrix".
>
>I tried the following script:
>
>Script:
>#Creation of a previous vector
>n.Tree<-2
>VectorX<-rep(1,n.Tree)
>
>#loop
>for (i in 1:2) {
> Ti<-MatOccurTree[Tree[i],1] #number of observation for Tree i
> Xi<-matrix(data=1,nrow=Ti,ncol=2)
> Xi[,2]<-treedata2$lnE[IdentTree==Tree[i]]
> VectorX[i]<-Xi
>}
>
>Console:
>
>
>>VectorX[i]<-Xi
>>
>>
>Warning message:
>le nombre d'objets ?? remplacer n'est pas multiple de la taille du
remplacement
>"number of object to replace isn't a multiple of the length of the
replacement"
>
>Would you have any solution to create a vector of matrix "VectorX"
?
>
>Thanks for your help.
>
>Ghislain Vieilledent.
>
> [[alternative HTML version deleted]]
>
>
>
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