Hi All,
I have conducted the following survival analysis which appears to be OK
(acknow. to AZ & PR for solving my earlier issues).
surv.mod1 <- survreg( Surv(timep1, relall6)~randgrpc, data=Dataset,
dist="weibull", scale = 1)
summary(surv.mod1)
Call:
survreg(formula = Surv(timep1, relall6) ~ randgrpc, data = Dataset,
dist = "weibull", scale = 1)
Value Std. Error z p
(Intercept) 7.36 0.259 28.42 1.27e-177
randgrpc -0.59 0.156 -3.80 1.47e-04
Scale fixed at 1
Weibull distribution
Loglik(model)= -1268.6 Loglik(intercept only)= -1276
Chisq= 14.72 on 1 degrees of freedom, p= 0.00012
Number of Newton-Raphson Iterations: 5
n= 400
My question is how does one fits a weibull survival function to the
model,
such that the output would be an alfa and beta (weibull parameters)?
Thanks
S.
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http://mail.nana.co.il
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