R help - Dec 2005 - Correlation matrix from a vector of pairwise correlations

I've a vector of pairwise correlations in the order low-index element 
precedes the high-index element, say:

corr(1,2)=0.1, corr(1,3)=0.2, corr(2,3)=0.3, corr(3,4)=0.4

How can I construct the corresponding correlation matrix?

I tried using the "combn"-function in "combinat" package:

library(combinat)
combn(c(0.1,0.2,0.3,0.4),2)

, but to no avail...

Thank you for your help,
Serguei Kaniovski
-- 
___________________________________________________________________

??sterreichisches Institut f??r Wirtschaftsforschung (WIFO)

Name: Serguei Kaniovski                 Postadresse: Postfach  91
Tel.: +43-1-7982601-231                 A-1103  Wien
Fax : +43-1-7989386                     Standort: Arsenal Objekt 20 

Mail: Serguei.Kaniovski at wifo.ac.at      A-1030  Wien

http://www.wifo.ac.at/

Serguei Kaniovski <kaniovsk <at> wifo.ac.at> writes:
> 
> I've a vector of pairwise correlations in the order low-index element 
> precedes the high-index element, say:
> 
> corr(1,2)=0.1, corr(1,3)=0.2, corr(2,3)=0.3, corr(3,4)=0.4
> 
> How can I construct the corresponding correlation matrix?
  Not absolutely sure what you want to do, but guessing a little
bit (should your list above include corr(1,4) and corr(2,4) as well?)
If you have

corrs <- c(c12=0.1,c13=0.2,c14=0.3,c23=0.4,c24=0.5,c34=0.6)
## names unnecessary but included for clarity
m = diag(4)   ## 4x4 diagonal matrix
m[lower.tri(m)] = corrs  ## fill in lower triangle

## two ways to make it symmetric:
m = t(m)                 ## flip around matrix
m[lower.tri(m)] = corrs  ## fill in lower triangle

## OR
 m[row(m)>col(m)] = t(m)[row(m)<col(m)]

don't know which is more efficient, but either should work ---
if that's what you were trying for

 Ben Bolker