R help - Nov 2005 - dataframe conversion

The data structures in R are still very puzzling to me. Can anyone tell 
me how I can easily convert these two dataframes to one single dataframe 
with two columns (mean and sd) with 7 rows?

 > meanprofile
       V1       V2       V3       V4       V5       V6       V7
2292.001 2178.620 1654.310 1784.004 1160.052 1142.061 1046.675
 > sdprofile
       V1       V2       V3       V4       V5       V6       V7
310.6714 347.2072 197.2464 532.3916 161.2955 227.3634 108.5017

Thanks!
Pieter

> The data structures in R are still very puzzling to me. Can anyone tell 
> me how I can easily convert these two dataframes to one single dataframe 
> with two columns (mean and sd) with 7 rows?
> 
>  > meanprofile
>        V1       V2       V3       V4       V5       V6       V7
> 2292.001 2178.620 1654.310 1784.004 1160.052 1142.061 1046.675
>  > sdprofile
>        V1       V2       V3       V4       V5       V6       V7
> 310.6714 347.2072 197.2464 532.3916 161.2955 227.3634 108.5017
There are several ways to go about this. Here's one:
t(rbind(meanprofile, sdprofile))

?rbind and ?t
HTH, Andy

Pieter Provoost wrote:
> The data structures in R are still very puzzling to me. Can anyone tell 
> me how I can easily convert these two dataframes to one single dataframe 
> with two columns (mean and sd) with 7 rows?
> 
>  > meanprofile
>        V1       V2       V3       V4       V5       V6       V7
> 2292.001 2178.620 1654.310 1784.004 1160.052 1142.061 1046.675
>  > sdprofile
>        V1       V2       V3       V4       V5       V6       V7
> 310.6714 347.2072 197.2464 532.3916 161.2955 227.3634 108.5017

This is quite an unusual task, because you won't have data structure in 
a data.frame most of the times. In particular, you cannot make a row 
from a data.frame to a column generally.

In this case, we just convert the data.frame to matrix. I think most 
easily you can write:

   dat <- t(rbind(meanprofile, sdprofile))
   colnames(dat) <- c("meanprofile", "sdprofile")

Uwe Ligges


> Thanks!
> Pieter
> 
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