Something similar to this
(but I haven't tested)
mydf <- data.frame(xx=rnorm(100), yy=rnorm(100), zz=rnorm(100))
for (nm in names(mydf)) {
fnm <- file.path('c:',paste(nm,'.emf',sep=''))
cat('Creating histogram in file',fnm,'\n')
win.metafile( filename=fnm)
hist(mydf[[nm]]) # or
hist(mydf[,nm])
dev.off()
}
-Don
At 11:54 AM -0400 10/5/05, Paul E. Green wrote:>I can output two histograms of variables
>AXFILTERED and AZPTOP as follows:
>
>win.metafile(filename="C:/AXFILTERED.emf",pointsize=12)
>hist(AXFILTERED,breaks=40)
>dev.off()
>
>win.metafile(filename="C:/AZPTOP.emf",pointsize=12)
>hist(AZPTOP,breaks=40)
>dev.off()
>
>But, I actually have a dataframe of 120 variables that I
>would like histograms of. Any solutions that would
>save me from repeating this code 120 times? Can I
>pass arguments inside quotes? Can I write a function
>to do this?
>
>Paul Green
> [[alternative HTML version deleted]]
>
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--
--------------------------------------
Don MacQueen
Environmental Protection Department
Lawrence Livermore National Laboratory
Livermore, CA, USA