you could use something like the following (in case of two-group
comparisons make the proper adjustements):
pois.test <- function(x, alternative = c("two.sided",
"less",
"greater"), mu){
alternative <- match.arg(alternative)
if (missing(mu) || (length(mu) != 1 || is.na(mu)))
stop("'mu' must be a single number")
nx <- length(x)
mu.x <- mean(x)
stat <- (mu.x - mu) / sqrt(mu.x/nx)
p.value <- switch(alternative,
"two.sided" = 2 * pnorm(-abs(stat)),
"less" = pnorm(stat),
"greater" = pnorm(stat, lower = FALSE))
list("sample mean" = mu.x, "null mean" = mu,
"alternative" =
alternative,
statistic = stat, p.value = p.value)
}
################
y <- rpois(50, 5)
pois.test(y, alt = "g", mu = 4)
y <- rpois(30, 15)
pois.test(y, alt = "l", mu = 16)
I hope it helps.
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/16/336899
Fax: +32/16/337015
Web: http://www.med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
----- Original Message -----
From: "Jan Wijffels" <Jan.Wijffels at ucs.kuleuven.be>
To: <r-help at stat.math.ethz.ch>
Sent: Monday, September 12, 2005 10:01 AM
Subject: [R] poisson mean hypothesis
> Dear R-users,
> Is there a way to get p-values for a one-sided hypothesis test about
> a
> poisson mean?
>
> Thanks,
>
> Jan Wijffels
> University Center for Statistics
> W. de Croylaan 54
> 3001 Heverlee
> Belgium
> tel: +32 (0)16 322784
> fax: +32 (0)16 322831
> <http://www.kuleuven.be/ucs> http://www.kuleuven.be/ucs
>
>
>
> Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm
>
>
> [[alternative HTML version deleted]]
>
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