problem solved. thank you Jim and Spencer for your
answers.
> This gives the same answer for what you have
> supplied so far...
> >
> dat$d<-ifelse((dat$b-dat$a)>=1000,dat$b-dat$a+1,0)
> > dat
> a b c d
> 1 1 1001 1001 1001
> 2 2 1001 0 0
> 3 3 1001 0 0
> 4 4 1001 0 0
> 5 1 1002 1002 1002
> 6 2 1002 1001 1001
> 7 3 1002 0 0
> 8 4 1002 0 0
> 9 1 1003 1003 1003
> 10 2 1003 1002 1002
> 11 3 1003 1001 1001
> 12 4 1003 0 0
> 13 1 1004 1004 1004
> 14 2 1004 1003 1003
> 15 3 1004 1002 1002
> 16 4 1004 1001 1001
>
> -----Original Message-----
> From: r-help-bounces at stat.math.ethz.ch
> [mailto:r-help-bounces at stat.math.ethz.ch] On
> Behalf Of alex diaz
> Sent: June 27, 2005 4:54 PM
> To: r-help at stat.math.ethz.ch
> Subject: [R] simplifying the code
>
> dear list:
>
> I made some corrections in the previous post
> that had
> some mistakes.
>
> I need help to achieve a simpler code to
> complete a
> task I'm performing.
> here is an example:
>
> dat<-expand.grid(a=seq(1,4),b=seq(1001,1004))
>
> #I want to add a new column dat$c in that:
>
> t1<-ifelse(dat$a==1&dat$b==1001,1001,0)
> t2<-ifelse(dat$a==2&dat$b==1002,1001,0)
> t3<-ifelse(dat$a==3&dat$b==1003,1001,0)
> t4<-ifelse(dat$a==4&dat$b==1004,1001,0)
> t5<-ifelse(dat$a==1&dat$b==1002,1002,0)
> t6<-ifelse(dat$a==2&dat$b==1003,1002,0)
> t7<-ifelse(dat$a==3&dat$b==1004,1002,0)
> t8<-ifelse(dat$a==1&dat$b==1003,1003,0)
> t9<-ifelse(dat$a==2&dat$b==1004,1003,0)
> t10<-ifelse(dat$a==1&dat$b==1004,1004,0)
>
> dat$c<-t1+t2+t3+t4+t5+t6+t7+t8+t9+t10
>
> My real data frame is much larger... I hope
> someone
> can help me with this.
>
> thanks for your help
>
> a. diaz
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