I think you misunderstand what barchart does. It expects a formula, not a
named vector, as its first argument.
nm <- names(T3)
z <- factor(nm, levels=nm)
barchart(z ~ T3, xlab="Mean Values", col="dark blue")
is probably what you are looking for. The factor z is constructed to be
in the order you want.
That barchart() accepts a named vector appears to be undocumented. For an
unnamed vector it does not behave similarly to barplot().
On Mon, 2 Feb 2004, Bliese, Paul D MAJ USAMH wrote:
> Sorry if this is a FAQ -- I checked the archives and help files, but was
> stumped.
>
> In the data T3 (provided below) the values are sorted from lowest to
> highest.
>
> > T3
> 10 7 19 13 5 3 15 18
> 2 24
> 2.650568 2.666237 2.731649 2.749221 2.777130 2.801124 2.804472 2.813891
> 2.838316 2.839654
> 36 20 25 32 26 12 14 29
> 23 6
> 2.843043 2.868335 2.882906 2.896539 2.922535 2.931397 2.939590 2.944353
> 2.983473 3.015235
> 39 4 17 9 30 21 33 22
> 8 35
> 3.017590 3.020495 3.038758 3.066808 3.084511 3.086072 3.106873 3.127783
> 3.167053 3.173310
> 28 16 37 1 31 40 27 11
> 34 38
> 3.173323 3.221106 3.236643 3.274417 3.274772 3.283696 3.307872 3.355327
> 3.382744 3.498301
>
>
> If I use barchart in the trellis library, the bars are arranged by factor
> order of the labels (1,10,11,12,etc.).
>
> > barchart(T3,xlab="Mean Values",col="dark blue")
>
> Would it be possible to have the bars arranged from highest to lowest in
> terms of the values (2.65, 2.66, 2.73, etc.) as it is done in barplot?
>
> >barplot(T3,xlab="Mean Values",col="dark
blue",horiz=T,cex.names=.5)
>
> I would like to use barchart instead of barplot because of some of the
> additional features of the lattice library.
>
> Thanks,
>
> Paul
>
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>
--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595