If you're having so much trouble, perhaps it's because you want to get a
vector result? This requires a little more, and if so, perhaps one of the
following provides what you are looking for:
> x <- data.frame(a=1:3,b=4:6)
> # row as a data frame
> x[2,]
a b
2 2 5
> # row as a list
> x[2,,drop=T]
$a
[1] 2
$b
[1] 5
> # row as a vector
> unlist(x[2,,drop=T])
a b
2 5
> # row as a vector again
> unlist(x[2,])
a b
2 5
> # row as a matrix (if x contains any non-numeric columns, this will be a
character matrix)
> as.matrix(x[2,])
a b
2 2 5
> # row as a vector (if x contains any non-numeric columns, this will be a
character vector)
> as.matrix(x)[2,]
a b
2 5
> # row as a numeric vector (non-numeric columns in x will be converted to
numeric data, see ?data.matrix for how)
> data.matrix(x[2,])
a b
2 2 5
>
Tony Plate
At Thursday 05:40 PM 10/9/2003 +0100, Mark Lee wrote:>I have this right on the desk in front of me. I have gone through most
>of this actually and have been looking for the answer for several
>weeks now before resorting to this. The only reference I've found to
>this is on page 20 under array indexing but didn't see the relation to
>dataframes. Thanks,
>
>Mark
>
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