Hi David,
Please help me out to resolve the following
statistical problem.
For the following data
X Y
0 21.5
0 21.78
0.03 21.5
0.09 16.3
0.27 9.9
0.81 6.13
2.43 5.17
How to put the logistic curve was fitted for the
following model
C
Y = --------------
(1 + (X/X0)^b)
Where Y is the total no. of juveniles per parent
animals alive at the end of the test and X is the
concentartion.
C = the expected no. of juveniles when X = 0
X0 = the EC50 in the population
b = the slope parameter
I expect the results as early as possible.
Thanks & regards
K.V.Anantha Padmanabha
Rallis India Limited
Have you considered "nls" and / or "optim"? hope this helps. spencer graves K.V.ANANTHA PADMANABHA wrote:> Hi David, > > Please help me out to resolve the following > statistical problem. > > For the following data > > X Y > 0 21.5 > 0 21.78 > 0.03 21.5 > 0.09 16.3 > 0.27 9.9 > 0.81 6.13 > 2.43 5.17 > > How to put the logistic curve was fitted for the > following model > > C > Y = -------------- > (1 + (X/X0)^b) > > > Where Y is the total no. of juveniles per parent > animals alive at the end of the test and X is the > concentartion. > > C = the expected no. of juveniles when X = 0 > X0 = the EC50 in the population > b = the slope parameter > > > > I expect the results as early as possible. > > Thanks & regards > > K.V.Anantha Padmanabha > Rallis India Limited > > ______________________________________________ > R-help at stat.math.ethz.ch mailing list > https://www.stat.math.ethz.ch/mailman/listinfo/r-help