Adejumo Adebowale Olusola
2003-Jul-10 13:45 UTC
[R] The question is on Symmetry model for square table.
Please help,
I tried a program on S-plus, and it worked. Also I tried the same
program on R but not worked. Here is the programme. I put it in a
function form. The model and assumption are at the bottom.
where
counts<-c(22,2,2,0,5,7,14,0,0,2,36,0,0,1,17,10)
which is name.data, i is row size and j is the column size.
symmetry
function(i, j, name.data)
{
row <- (c(1:i))
col <- (c(1:j))
name.data <- expand.grid(A = row, B = col)
name.data$counts <- c(counts)
name.data$symm <- paste(pmin(as.numeric(name.data$A),
as.numeric(name.data$B)), pmax(as.numeric(name.data$A),
as.numeric(name.data$B)), sep = ",")
symmetry <- glm(counts ~ symm, family = poisson(link = log), data =
name.data)
}
> summary(symmetry(4,4,counts))
Call: glm(formula = counts ~ symm, family = poisson(link = log), data =
name.data)
Deviance Residuals:
Min 1Q Median 3Q Max
-4.123106 -0.9044956 -3.846197e-008 0.6543513 2.562617
Coefficients:
Value Std. Error t value
(Intercept) 0.7912419 2.1128915 0.3744830
symm1 -0.9191397 0.2169745 -4.2361653
symm2 -0.7239676 0.2465491 -2.9364038
symm3 -2.3094242 5.2703608 -0.4381909
symm4 0.5614798 1.0575027 0.5309488
symm5 0.3965751 0.7045443 0.5628817
symm6 -0.1128162 0.5223163 -0.2159920
symm7 0.4499711 0.3777980 1.1910362
symm8 0.1895939 0.2946399 0.6434767
symm9 0.1679270 0.2368599 0.7089720
(Dispersion Parameter for Poisson family taken to be 1 )
Null Deviance: 190.398 on 15 degrees of freedom
Residual Deviance: 39.17989 on 6 degrees of freedom
Number of Fisher Scoring Iterations: 6
_________________________________________________________________________
Also in R. program, here is the same program together with the complain.
name.data=counts (above).
> symmetry
function(i,j,name.data){
A<-(c(1:i))
B<-(c(1:j))
name.data<-expand.grid(A=A,B=B)
name.data$counts<-(c(counts))
name.data$symm<-paste(pmin(as.numeric(name.data$A),as.numeric(name.data$B)),
pmax(as.numeric(name.data$A),as.numeric(name.data$B)),sep=",")
symmetry<-glm(counts~symm,data=name.data,family=poisson(link=log))
}
> symmetry(4,4,counts)
Error in model.frame(formula, rownames, variables, varnames, extras,
extranames, : invalid variable type
I tried to print out the table with symm pathern. and the function for
symm below.
> i<-4
> j<-4
> A<-(c(1:i))
> B<-(c(1:j))
> name.data<-expand.grid(A=A,B=B)
> name.data$counts<-(c(counts))
>name.data$symm<-paste(pmin(as.numeric(name.data$A),as.numeric(name.data$B)),
+ pmax(as.numeric(name.data$A),as.numeric(name.data$B)),sep=",")
> name.data
A B counts symm
1 1 1 22 1,1
2 2 1 2 1,2
3 3 1 2 1,3
4 4 1 0 1,4
5 1 2 5 1,2
6 2 2 7 2,2
7 3 2 14 2,3
8 4 2 0 2,4
9 1 3 0 1,3
10 2 3 2 2,3
11 3 3 36 3,3
12 4 3 0 3,4
13 1 4 0 1,4
14 2 4 1 2,4
15 3 4 17 3,4
16 4 4 10 4,4
>
> symm
function (x, levels = sort(unique.default(x), na.last = TRUE),
labels = levels, exclude = NA, ordered = is.ordered(x))
{
if (is.null(x))
x <- list()
exclude <- as.vector(exclude, typeof(x))
levels <- levels[is.na(match(levels, exclude))]
f <- match(x, levels)
names(f) <- names(x)
nl <- length(labels)
attr(f, "levels") <- if (nl == length(levels))
as.character(labels)
else if (nl == 1)
paste(labels, seq(along = levels), sep = "")
else stop(paste("invalid labels; length", nl, "should be 1
or",
length(levels)))
class(f) <- c(if (ordered) "ordered", "factor")
f
}
-----------------------------------------------------------------------------
The model and Assumptions
log(m_ij)= lambda + lambda_i + lambda_j + lambda_ij
where,
lambda_ij = lambda_ji for i not equal to j
and lambda_i(A) = lambda_i(B)
Likelihood equation is
m_ij =(n_ij + n_ji)/2
For symmetry m_(ij)=m_(ji)
"R program" does not recognised "symm" pathern, that is
(1,1), (1,2) and
so on but "S-plus" do. So please I need your assistance.
Thanks for your usual contibutions.
Yours
Sola.
--
---------------------------------
Adebowale Olusola Adejumo
Department of Statistics
LMU,University of Muenchen
Ludwigstra?e 33/III
D - 80539 M?nchen
Germany.
Tel: ++49 89 2180 3165
Fax: ++49 89 2180 5042
http://www.stat.uni-muenchen.de/
Spencer Graves
2003-Jul-10 15:08 UTC
[R] The question is on Symmetry model for square table.
Did you try "traceback()"? This might help you identify the offending line in your function. If that doesn't help, I step through the function one line at a time (copy and paste from an editor) until R bombs on me. If it doesn't bomb, then there is a "scoping" problem: Are you using global variables in a function? If yes, pass them explicitly as arguments. I recently potentially similar problems this way. hope this helps. spencer graves Adejumo Adebowale Olusola wrote:> Please help, > I tried a program on S-plus, and it worked. Also I tried the same > program on R but not worked. Here is the programme. I put it in a > function form. The model and assumption are at the bottom. > > where > counts<-c(22,2,2,0,5,7,14,0,0,2,36,0,0,1,17,10) > which is name.data, i is row size and j is the column size. > > symmetry > function(i, j, name.data) > { > row <- (c(1:i)) > col <- (c(1:j)) > name.data <- expand.grid(A = row, B = col) > name.data$counts <- c(counts) > name.data$symm <- paste(pmin(as.numeric(name.data$A), > as.numeric(name.data$B)), pmax(as.numeric(name.data$A), > as.numeric(name.data$B)), sep = ",") > symmetry <- glm(counts ~ symm, family = poisson(link = > log), data = name.data) > } > > summary(symmetry(4,4,counts)) > > Call: glm(formula = counts ~ symm, family = poisson(link = log), data = > name.data) > Deviance Residuals: > Min 1Q Median 3Q Max > -4.123106 -0.9044956 -3.846197e-008 0.6543513 2.562617 > > Coefficients: > Value Std. Error t value > (Intercept) 0.7912419 2.1128915 0.3744830 > symm1 -0.9191397 0.2169745 -4.2361653 > symm2 -0.7239676 0.2465491 -2.9364038 > symm3 -2.3094242 5.2703608 -0.4381909 > symm4 0.5614798 1.0575027 0.5309488 > symm5 0.3965751 0.7045443 0.5628817 > symm6 -0.1128162 0.5223163 -0.2159920 > symm7 0.4499711 0.3777980 1.1910362 > symm8 0.1895939 0.2946399 0.6434767 > symm9 0.1679270 0.2368599 0.7089720 > > (Dispersion Parameter for Poisson family taken to be 1 ) > > Null Deviance: 190.398 on 15 degrees of freedom > > Residual Deviance: 39.17989 on 6 degrees of freedom > > Number of Fisher Scoring Iterations: 6 > > _________________________________________________________________________ > Also in R. program, here is the same program together with the complain. > > name.data=counts (above). > > > symmetry > function(i,j,name.data){ > A<-(c(1:i)) > B<-(c(1:j)) > name.data<-expand.grid(A=A,B=B) > name.data$counts<-(c(counts)) > name.data$symm<-paste(pmin(as.numeric(name.data$A),as.numeric(name.data$B)), > > pmax(as.numeric(name.data$A),as.numeric(name.data$B)),sep=",") > symmetry<-glm(counts~symm,data=name.data,family=poisson(link=log)) > } > > > symmetry(4,4,counts) > Error in model.frame(formula, rownames, variables, varnames, extras, > extranames, : invalid variable type > > I tried to print out the table with symm pathern. and the function for > symm below. > > > i<-4 > > j<-4 > > A<-(c(1:i)) > > B<-(c(1:j)) > > name.data<-expand.grid(A=A,B=B) > > name.data$counts<-(c(counts)) > >name.data$symm<-paste(pmin(as.numeric(name.data$A),as.numeric(name.data$B)), > + pmax(as.numeric(name.data$A),as.numeric(name.data$B)),sep=",") > > name.data > A B counts symm > 1 1 1 22 1,1 > 2 2 1 2 1,2 > 3 3 1 2 1,3 > 4 4 1 0 1,4 > 5 1 2 5 1,2 > 6 2 2 7 2,2 > 7 3 2 14 2,3 > 8 4 2 0 2,4 > 9 1 3 0 1,3 > 10 2 3 2 2,3 > 11 3 3 36 3,3 > 12 4 3 0 3,4 > 13 1 4 0 1,4 > 14 2 4 1 2,4 > 15 3 4 17 3,4 > 16 4 4 10 4,4 > > > > > symm > function (x, levels = sort(unique.default(x), na.last = TRUE), > labels = levels, exclude = NA, ordered = is.ordered(x)) > { > if (is.null(x)) > x <- list() > exclude <- as.vector(exclude, typeof(x)) > levels <- levels[is.na(match(levels, exclude))] > f <- match(x, levels) > names(f) <- names(x) > nl <- length(labels) > attr(f, "levels") <- if (nl == length(levels)) > as.character(labels) > else if (nl == 1) > paste(labels, seq(along = levels), sep = "") > else stop(paste("invalid labels; length", nl, "should be 1 or", > length(levels))) > class(f) <- c(if (ordered) "ordered", "factor") > f > } > > ----------------------------------------------------------------------------- > > The model and Assumptions > > log(m_ij)= lambda + lambda_i + lambda_j + lambda_ij > > where, > lambda_ij = lambda_ji for i not equal to j > and lambda_i(A) = lambda_i(B) > Likelihood equation is > > m_ij =(n_ij + n_ji)/2 > > For symmetry m_(ij)=m_(ji) > > "R program" does not recognised "symm" pathern, that is (1,1), (1,2) and > so on but "S-plus" do. So please I need your assistance. > > Thanks for your usual contibutions. > > Yours > > Sola. > >
Apparently Analagous Threads
- Unexpected behaviour for RowSideColors in function heatmap
- hclust and heatmap - slightly different dendrograms?
- [test-suite] making polybench/symm succeed with "-Ofast" and "-ffp-contract=on"
- [test-suite] making polybench/symm succeed with "-Ofast" and "-ffp-contract=on"
- [test-suite] making polybench/symm succeed with "-Ofast" and "-ffp-contract=on"