R help - Apr 2003 - easy question

Dear R.List,
I am starting to use R. I have an easy question. In a dataset of 15
variables, I am not able run correctly the index i of the do loop. 
Do you have any suggestion? 

NC <- function(x)

    for (i in 1:15) {  
    print(dim(table(dt[,"Vi"])))
    
}


Thank you in advance,
Fabrizio


---------------------------------------------------------------
Fabrizio De Amicis

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E-mail: fabrizio.deamicis at git.generali.ch  




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Hi,

On Tue, 29 Apr 2003, De Amicis Fabrizio (G.I.T.) wrote:
> Dear R.List,
> I am starting to use R. I have an easy question. In a dataset of 15
> variables, I am not able run correctly the index i of the do loop. 
> Do you have any suggestion? 
> 
> NC <- function(x)
> 
>     for (i in 1:15) {  
>     print(dim(table(dt[,"Vi"])))
Why do you have "Vi" with quotes?  Your counter i isn't used
anywhere in
the loop.  I am assuming your dataset of 15 variables is a data frame or 
matrix?  Then you'll need dt[, i] instead.  It will read the $i^{th}$ 
column each time it runs through the loop.

On a side note.  The above function isn't right.  The NC function will 
need a variable x, which isn't used anywhere in the function.  You don't
need to put the for() loop into the function at all.  (I'm assuming you 
have got a data frame or matrix called dt).
>     
> }


-- 
Cheers,

Kevin

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Dear Fabrizio

At 12:07 PM 4/29/2003 +0200, De Amicis Fabrizio (G.I.T.)
wrote:
>Dear R.List,
>I am starting to use R. I have an easy question. In a dataset of 15
>variables, I am not able run correctly the index i of the do loop.
>Do you have any suggestion?
>
>NC <- function(x)
>
>     for (i in 1:15) {
>     print(dim(table(dt[,"Vi"])))
>
>}
>
The short answer is that you need to paste the number in i to "V" in
order
to create a proper column index. I assume that the columns of dt are named 
"V1", ..., "V15":

     print(dim(table(dt[,paste("V",i,sep="")])))

Alternatively, you could use something like

     for (i in paste("V",1:15,sep=""))
print(dim(table(dt[,i])))

or even more simply, just index the columns by number

     for (i in 1:15) print(dim(table(x[,i])))

Some other points, however:

(1) The argument to your function is x, but you're indexing a variable 
called dt.

(2) A simpler approach to counting the unique elements in each column is

         apply(dt, 2, function(x) length(unique(x)))

(3) Since this apparently applies to a particular matrix or data frame, why 
write a function to perform the operation?

I hope that this helps,
  John

-----------------------------------------------------
John Fox
Department of Sociology
McMaster University
Hamilton, Ontario, Canada L8S 4M4
email: jfox at mcmaster.ca
phone: 905-525-9140x23604
web: www.socsci.mcmaster.ca/jfox