juli, assuming your "gen" is the identification variable for clusters,
the
following is an illustration.
Jun
> dat <- data.frame(gen=rep(1:5, rep(2,5)), maxh=rnorm(10),
resp=rep(c("y", "n"), 5))> dat
gen maxh resp
1 1 -1.53878091 y
2 1 -0.71171477 n
3 2 0.93065758 y
4 2 -1.65696752 n
5 3 -0.09981616 y
6 3 0.08186816 n
7 4 0.11563345 y
8 4 0.04991344 n
9 5 0.67936629 y
10 5 -1.29308856 n> dat.w <- reshape(dat, idvar="gen", timevar="resp",
v.names="maxh",
direction="wide")> dat.w
gen maxh.n maxh.y
1 1 -0.71171477 -1.53878091
3 2 -1.65696752 0.93065758
5 3 0.08186816 -0.09981616
7 4 0.04991344 0.11563345
9 5 -1.29308856 0.67936629>
On Sat, 12 Oct 2002, juli g. pausas wrote:
> I'd like to convert a data.frame from (long format):
> gen maxh resp
> 1 12.3 y
> . . .
> . . .
> where resp is a factor with levels "y" and "n"
> to the wide format:
>
> gen maxh.y maxh.n
> . . .
> . . .
>
> I've done it as follows:
>
> maxh.y <- split(maxh, resp)$y
> gy <- split(gen, resp)$y
> yes <- data.frame(hr, gen=gy)
>
> maxh.n <- split(maxh, resp)$n
> gn <- split(gen, resp)$n
> no <- data.frame(hn, gen=gn)
>
> wide <- merge(yes, no, by= "gen") # gen maxh.y maxh.n
>
> This worked well, but would it be possible to do it with reshape? I've
> tried but I didn't succeed.
> Thanks
>
> Juli
>
>
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
> r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
> Send "info", "help", or "[un]subscribe"
> (in the "body", not the subject !) To: r-help-request at
stat.math.ethz.ch
>
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !) To: r-help-request at
stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._