R help - Aug 2002 - help with lagged scatterplot

Hi!

I'm not sure, if I understand you correctly, you want to plot nao at time t
against mei at time t-h. So lag.plot is not the right function because it plots
e.g. nao(t) against nao(t-h). Well, something along the lines

attach(data)
plot(mei[1:(length(mei)-h)],nao[-(1:h)])

should do what you want. (Negativ indices remove values from vectors or
matrices.)

Regards,

Winfried
On 06-Aug-02 Antonio wrote:
> Hi,
> 
> How do I can make a lagged scatterplot of two variables:      
> 
>  Yt (nao) versus Xt-h (mei)
> 
> if they have the following structure:
> 
>>series
> 
>            mei        nao
> Jan 1950 -1.036  0.55
> Feb 1950 -1.133  3.31
> Mar 1950 -1.259  0.81
> Apr 1950 -1.027  1.60
> May 1950 -1.399 -1.73
> Jun 1950 -1.366  1.26
> Jul 1950 -1.300 -0.87
> .
> .
> .
> 
> I've tried with lag.plot but I don't understanf how to use it
> 
> Thanks in advance
> 
> Antonio Rodriguez
> CICEM Agua del Pino
> Huelva, Spain
> Antonio Rodríguez Verdugo
> Huelva, Spain
> yerupaja01 at terra.es
>
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.
> -
> r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
> Send "info", "help", or "[un]subscribe"
> (in the "body", not the subject !)  To: r-help-request at
stat.math.ethz.ch
>
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._.
> _
---------------------------------------------------------------------
E-Mail: Winfried Theis <theis at statistik.uni-dortmund.de>
Date: 06-Aug-02

Dipl.-Math. Winfried Theis
SFB 475, Fachbereich Statistik, Universit"at Dortmund, 44221 Dortmund
Tel.: +49-231-755-5903 FAX: +49-231-755-4387
----------------------------------------------------------------------
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at
stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._

Hi,

How do I can make a lagged scatterplot of two variables:	

 Yt (nao) versus Xt-h (mei)

if they have the following structure:
>series
	     mei	nao
Jan 1950 -1.036  0.55
Feb 1950 -1.133  3.31
Mar 1950 -1.259  0.81
Apr 1950 -1.027  1.60
May 1950 -1.399 -1.73
Jun 1950 -1.366  1.26
Jul 1950 -1.300 -0.87
.
.
.

I've tried with lag.plot but I don't understanf how to use it

Thanks in advance

Antonio Rodriguez
CICEM Agua del Pino
Huelva, Spain
Antonio Rodr?guez Verdugo
Huelva, Spain
yerupaja01 at terra.es
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at
stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._

Dear Winfried,

Thanks!!

Seems to work fine. So if I had correctly understand, if I want to plot NAO
vs MEI-6 (6 months earlier) I need to write.

plot(mei[1:(length(mei)-6)],nao[-(1:6)])

It's OK?

As I have negative values for both variables I don't understand your note:
>(Negativ indices remove values from vectors or
>matrices.)
What does it means. My negative values are interfering some way the output?

Thanks in advance

Antonio


Antonio Rodr?guez Verdugo
Huelva, Spain
yerupaja01 at terra.es
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at
stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._