R help - Jun 2002 - rbind

Hello,

I am sure this is a trivial question, but I don't get it...
Having a dataframe (b.70) like that:
> b.70[1:4,2:3]
         ARG        AUS
1960     19041     25949
1961     19675     25451
1962     19302     26463
1963     18121     27644

Now I want to calculate the log for each year and save the 
result in a new dataframe called 'x'.

x<- data.frame(w=NULL)
for(i in 1:3)
ja <- b.70[i:(i+1),2:3]
  af <- log(ja[2,]/ja[1,])
  x <-  rbind(x,af)

But this saves only the last value of 'af' in
'x'
> x
        ARG          AUS      
1963 -0.06313723  0.04366118

So, how can I preserve the old values of x?

Thanks a lot
Patrick

-------------
Patrick Hausmann
Friedrich-Wilhelm Str. 37 - D-28199 Bremen
Tel. +49 421 5980631 - Fax. +49 421 5980632
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> x<- data.frame(w=NULL)
> for(i in 1:3)
> ja <- b.70[i:(i+1),2:3]
>   af <- log(ja[2,]/ja[1,])
>   x <-  rbind(x,af)
> 
maybe you should tell "for" to loop over the second and third line,
too


for(i in 1:3)  {
 ja <- b.70[i:(i+1),2:3]
 af <- log(ja[2,]/ja[1,])
 x <-  rbind(x,af)
}


Torsten
> But this saves only the last value of 'af' in 'x'
> > x
>         ARG          AUS      
> 1963 -0.06313723  0.04366118
> 
> So, how can I preserve the old values of x?
> 
> Thanks a lot
> Patrick
> 
> -------------
> Patrick Hausmann
> Friedrich-Wilhelm Str. 37 - D-28199 Bremen
> Tel. +49 421 5980631 - Fax. +49 421 5980632
>
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
> r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
> Send "info", "help", or "[un]subscribe"
> (in the "body", not the subject !)  To: r-help-request at
stat.math.ethz.ch
>
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
> 
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
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