enrico.foscolo2 at libero.it
2009-Jan-21 10:47 UTC
[R] Function able to identify the row and the column in a matrix
Good morning to all, I should evaluate a function for every cell of a given matrix with n rows and n columns. This function, named fun(), has got two arguments: the number of the row and the number of the column which characterized every single cell. So the result should be fun(1,1) fun(1,2) ... fun(1,n) fun(2,1) fun(2,2) ... fun(2,n) ... ... ... ... fun(n,1) fun(n,2) ... fun(n,n) Does it exist a function which could build this new matrix, where each element in the cell (i,j) is fun(i,j), with 1<=i, j<=n? Thank you very much, Enrico Foscolo
Petr PIKAL
2009-Jan-21 10:52 UTC
[R] Odp: Function able to identify the row and the column in a matrix
Hi ?outer regards Petr r-help-bounces at r-project.org napsal dne 21.01.2009 11:47:03:> Good morning to all, > > I should evaluate a function for every cell of a given > matrix with n rows and n columns. > > This function, named fun(), has got two > arguments: the number of the row and the number of the column which > characterized every single cell. > > So the result should be > > fun(1,1) fun(1,2) > ... fun(1,n) > fun(2,1) fun(2,2) ... fun(2,n) > ... ... ... > ... > fun(n,1) fun(n,2) ... fun(n,n) > > Does it exist a function which could build > this new matrix, where each element in the cell (i,j) is fun(i,j), with1<=i,> j<=n? > > Thank you very much, > > Enrico Foscolo > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guidehttp://www.R-project.org/posting-guide.html> and provide commented, minimal, self-contained, reproducible code.
enrico.foscolo2 at libero.it
2009-Jan-21 10:52 UTC
[R] Function able to identify the row and the column in a matrix
Good morning to all, I should evaluate a function for every cell of a given matrix with n rows and n columns. This function, named fun(), has got two arguments: the number of the row and the number of the column which characterized every single cell. So the result should be fun(1,1) fun(1,2) ... fun(1,n) fun(2,1) fun(2,2) ... fun(2,n) ... ... ... ... fun(n,1) fun(n,2) ... fun(n,n) Does it exist a function which could build this new matrix, where each element in the cell (i,j) is fun(i,j), with 1<=i, j<=n? Thank you very much, Enrico Foscolo