I have consulted the intro and nabble but have not found an answer to what
should be a simple question, here goes:
I am doing a crosscheck of a data frame and pulling out a single value based
on an inputted value ie based on x i will select y, or if x =2 then my code
returns 7.
x y
1 4
2 7
3 10
4 2
My code currently iterates through for as many times as the length of the x
dataframe. What i would like to do is then is to build a vector for those
values selected. so if vector x = 1,4,7 then "new-y" would equal 4,
2, 3.
x y
1 4
2 7
3 10
4 2
5 21
6 13
7 3
8 90
I need to ultimetly re-sort my x vector based on the values of y but the
function i am using is the subset function and i cant do it without y being
a vector itself and it is currently only a one value object.
#Creates test Candidates Vector
Candidates=c(100,101,102,103,104,105)
#Creates object equaling the number of candidate TAZs from the main script
Location Choice Model
NumCands1=length(Candidates)
Dev..At=9999999
for(i in 1:NumCands1){
#Renames Location Choice Model generated TAZ's object
Loc_Mod_TAZ=Candidates[i]
#Converts Development size from main script to Development density function
format
Dev_Size=Dev..At
#This is my "y" value in the example i gave above, this is the value
that i
need put into a # vector, a vector that should have as
many values as there are number of candidates
TAZDetermine_FEET=TAZ_VAC_FEET[TAZ_VAC_FEET$TAZ==Loc_Mod_TAZ,2]
#Creates new vector based on adaquate vacancy in the TAZ and the
development to be located
Newcands=subset(Loc_Mod_TAZ, TAZDetermine_FEET>=Dev_Size)
}
Thanks for the help
Cheers,
JR
--
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See ?is.element ?order and perhaps ?ave and> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.as it says on your own email! What you provide is not reproducible. HTH, Chuck On Tue, 25 Nov 2008, PDXRugger wrote:> > I have consulted the intro and nabble but have not found an answer to what > should be a simple question, here goes: > > I am doing a crosscheck of a data frame and pulling out a single value based > on an inputted value ie based on x i will select y, or if x =2 then my code > returns 7. > > x y > 1 4 > 2 7 > 3 10 > 4 2 > > My code currently iterates through for as many times as the length of the x > dataframe. What i would like to do is then is to build a vector for those > values selected. so if vector x = 1,4,7 then "new-y" would equal 4, 2, 3. > > x y > 1 4 > 2 7 > 3 10 > 4 2 > 5 21 > 6 13 > 7 3 > 8 90 > > I need to ultimetly re-sort my x vector based on the values of y but the > function i am using is the subset function and i cant do it without y being > a vector itself and it is currently only a one value object. > > #Creates test Candidates Vector > Candidates=c(100,101,102,103,104,105) > > #Creates object equaling the number of candidate TAZs from the main script > Location Choice Model > NumCands1=length(Candidates) > > Dev..At=9999999 > for(i in 1:NumCands1){ > > #Renames Location Choice Model generated TAZ's object > Loc_Mod_TAZ=Candidates[i] > > #Converts Development size from main script to Development density function > format > Dev_Size=Dev..At > > #This is my "y" value in the example i gave above, this is the value that i > need put into a # vector, a vector that should have as > many values as there are number of candidates > TAZDetermine_FEET=TAZ_VAC_FEET[TAZ_VAC_FEET$TAZ==Loc_Mod_TAZ,2] > > #Creates new vector based on adaquate vacancy in the TAZ and the > development to be located > Newcands=subset(Loc_Mod_TAZ, TAZDetermine_FEET>=Dev_Size) > > > } > > Thanks for the help > Cheers, > JR > -- > View this message in context: http://www.nabble.com/creating-a-new-vecotr-in-a-for-loop-tp20691663p20691663.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >Charles C. Berry (858) 534-2098 Dept of Family/Preventive Medicine E mailto:cberry at tajo.ucsd.edu UC San Diego http://famprevmed.ucsd.edu/faculty/cberry/ La Jolla, San Diego 92093-0901
Dear PDXRugger, If I understand correctly, try this: # Data x = c(1:5,1,4,7) # Option 1 require(car) y1=recode(x, "1=4; 4=2; 7=3") # Option 2 y2=ifelse(x==1,4, ifelse(x==4,2, ifelse(x==7,3,x))) # Are y1 and y2 equals? all.equal(y1,y2) # Ordering x by y1 x[order(y1)] See ?order, ?ifelse and ?recode in the 'car' package for more information. HTH, Jorge On Tue, Nov 25, 2008 at 6:19 PM, PDXRugger <J_R_36@hotmail.com> wrote:> > I have consulted the intro and nabble but have not found an answer to what > should be a simple question, here goes: > > I am doing a crosscheck of a data frame and pulling out a single value > based > on an inputted value ie based on x i will select y, or if x =2 then my code > returns 7. > > x y > 1 4 > 2 7 > 3 10 > 4 2 > > My code currently iterates through for as many times as the length of the x > dataframe. What i would like to do is then is to build a vector for those > values selected. so if vector x = 1,4,7 then "new-y" would equal 4, 2, 3. > > x y > 1 4 > 2 7 > 3 10 > 4 2 > 5 21 > 6 13 > 7 3 > 8 90 > > I need to ultimetly re-sort my x vector based on the values of y but the > function i am using is the subset function and i cant do it without y being > a vector itself and it is currently only a one value object. > > #Creates test Candidates Vector > Candidates=c(100,101,102,103,104,105) > > #Creates object equaling the number of candidate TAZs from the main script > Location Choice Model > NumCands1=length(Candidates) > > Dev..At=9999999 > for(i in 1:NumCands1){ > > #Renames Location Choice Model generated TAZ's object > Loc_Mod_TAZ=Candidates[i] > > #Converts Development size from main script to Development density > function > format > Dev_Size=Dev..At > > #This is my "y" value in the example i gave above, this is the value > that i > need put into a # vector, a vector that should have as > many values as there are number of candidates > TAZDetermine_FEET=TAZ_VAC_FEET[TAZ_VAC_FEET$TAZ==Loc_Mod_TAZ,2] > > #Creates new vector based on adaquate vacancy in the TAZ and the > development to be located > Newcands=subset(Loc_Mod_TAZ, TAZDetermine_FEET>=Dev_Size) > > > } > > Thanks for the help > Cheers, > JR > -- > View this message in context: > http://www.nabble.com/creating-a-new-vecotr-in-a-for-loop-tp20691663p20691663.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]