maybe something like this could help:
x <- data.frame(a = 1:9, beta = exp(-4:4),
logic = rep(c(TRUE, FALSE), c(5, 4)))
x.l <- split(x, x$logic)
plot(x$a, x$beta)
mapply(function(x, y) lines(x$a, x$b, col = y), x.l, 1:2)
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
----- Original Message -----
From: "Petr Pikal" <petr.pikal at precheza.cz>
To: <r-help at stat.math.ethz.ch>
Sent: Tuesday, September 26, 2006 5:40 PM
Subject: [R] lapply, plot and additional arguments
> Dear all
>
> Hopefully somebody will know the answer.
>
> I have some list
>
> x <- data.frame(a = 1:9, beta = exp(-4:4), logic =
> rep(c(TRUE,FALSE),
> c(5,4)))
> x.l <- split(x, x$logic)
> plot(x.l$a, x.l$beta)
>
> and I want to plot lines color coded according to logic variable
>
> lapply(x.l, function(x, ...) lines(x$a, x$beta, col=1:2))
> lapply(x.l, function(x,...) lines(x$a,x$beta), col=1:2)
> lapply(x.l, function(x,...) lines(x$a,x$beta, ...), col=1:2)
>
> Well, lapply seems to ignore my best attempts to persuade it to use
> different colours for each part of x.l list.
>
> Anybody knows how to code different colours when using lapply for
> such plotting?
>
> At present time I use a loop but maybe lapply could do it too.
>
> Best regards.
> Petr
>
> Petr Pikal
> petr.pikal at precheza.cz
>
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