R help - Jan 2011 - Regex to remove last character

Hi,

Have been having trouble trying to figure out the right regex parameters to
remove the last "." in timestamp with the following format:

Convert 09:30:00.377.853 to  09:30:00.377853

Thanks,
Chris



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On Jan 3, 2011, at 2:24 PM, rivercode wrote:
>
> Hi,
>
> Have been having trouble trying to figure out the right regex  
> parameters to
> remove the last "." in timestamp with the following format:
>
> Convert 09:30:00.377.853 to  09:30:00.377853
gsub("()(\\.)(.{3}$)", "\\1\\3" ,
"09:30:00.377.853")
[1] "09:30:00.377853"
>
> -- 
> View this message in context:
http://r.789695.n4.nabble.com/Regex-to-remove-last-character-tp3172466p3172466.html
=
David Winsemius, MD
West Hartford, CT

Try this:

format(strptime("09:30:00.377.853", "%T%OS"),
"%H:%M:%OS")

On Mon, Jan 3, 2011 at 5:24 PM, rivercode <aquanyc@gmail.com> wrote:
>
> Hi,
>
> Have been having trouble trying to figure out the right regex parameters to
> remove the last "." in timestamp with the following format:
>
> Convert 09:30:00.377.853 to  09:30:00.377853
>
> Thanks,
> Chris
>
>
>
> --
> View this message in context:
>
http://r.789695.n4.nabble.com/Regex-to-remove-last-character-tp3172466p3172466.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>


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Henrique Dallazuanna
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25° 25' 40" S 49° 16' 22" O

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