Hello, I am having some trouble using a model I created from plsr (of train) to analyze each invididual R^2 of the 10 components against the test data. For example: mice1 <- plsr(response ~factors, ncomp=10 data=MiceTrain) R2(mice1) ##this provides the correct R2 for the Train data for 10 components ## Now my next objective is to calculate my model's R2 for each component on the Test data. (In other words - test how good the model is on test data) The only thing I need are the MiceTest.response, and compare that with predict(mice1, ncomp=1, newdata=MiceTest , and I should be able to calculate R2.....but I can't figure out the correct command to do this. I tried the command below, which does provide a different R2 response, however, I'm not sure it is correct as I get a different R^2 value from another software MOE ( Molecular Operating Environment ). R2(mice1, estimate="test", MiceTest) Is the above the correct code to achieve what I'm doing? If so, then MOE probably uses a different function to calculate the model component's R^2 for Test data. Thanks in advance. -- View this message in context: http://r.789695.n4.nabble.com/R2-function-from-PLS-to-use-a-model-on-test-data-tp2281426p2281426.html Sent from the R help mailing list archive at Nabble.com.
I figured out the answer. Since I have both the predicted and actual values, I simply need to call the lm function, and summary to see R^2 which matches what MOE provided. myline.fit <-lm( y~x) summary(myline.fit) -- View this message in context: http://r.789695.n4.nabble.com/R2-function-from-PLS-to-use-a-model-on-test-data-tp2281426p2282684.html Sent from the R help mailing list archive at Nabble.com.
Bjørn-Helge Mevik
2010-Aug-03 08:25 UTC
[R] R2 function from PLS to use a model on test data
Addi Wei <addiwei at gmail.com> writes:> Hello, > I am having some trouble using a model I created from plsr (of train) to > analyze each invididual R^2 of the 10 components against the test data. For > example: > > mice1 <- plsr(response ~factors, ncomp=10 data=MiceTrain) > R2(mice1) ##this provides the correct R2 for the Train data for 10 > components > ## Now my next objective is to calculate my model's R2 for each component on > the Test data. (In other words - test how good the model is on test data) > The only thing I need are the MiceTest.response, and compare that with > predict(mice1, ncomp=1, newdata=MiceTest , and I should be able to calculate > R2.....but I can't figure out the correct command to do this. I tried the > command below, which does provide a different R2 response, however, I'm not > sure it is correct as I get a different R^2 value from another software MOE > ( Molecular Operating Environment ). > > R2(mice1, estimate="test", MiceTest) > > Is the above the correct code to achieve what I'm doing? If so, then MOE > probably uses a different function to calculate the model component's R^2 > for Test data.That is the way to get test set "R^2" for PLSR/PCR models, yes. If you read in the documentation of R2, you will find: The R^2 values returned by '"R2"' are calculated as 1 - SSE/SST, where SST is the (corrected) total sum of squares of the response, and SSE is the sum of squared errors for either the fitted values (i.e., the residual sum of squares), test set predictions or cross-validated predictions (i.e., the PRESS). This is, AFAIK, the most common way to define R^2. For training data, this is equivalent to cor(y, yhat)^2, but not for test data or cross-validation.>From your second email, I would guess that MOE uses cor(y, yhat)^2 insteadof 1 - SSE/SST. -- Bj?rn-Helge Mevik
Apparently Analagous Threads
- Column header strategy
- How to formulate quadratic function with interaction terms for the PLS fitting model?
- Help with PLSR with jack knife
- Quadratic function with interaction terms for the PLS fitting model?
- How to formulate quadratic function with interaction terms for the PLS fitting model?