R help - Dec 2008 - Transforming a string to a variable's name? help me newbie...

Dear all,

I'm a newbie in R.
I have a 45x2x2x8 design.
A dataframe stores the metadata of trials. And each trial has its own
data file: I used "read.table" to import every trial into R as a
dataframe (variable).

Now I dynamically ask R to retrieve trials that fit certain selection
criteria, so I use "subset", e.g.
tmptrialinfo <- subset(trialinfo, (Subject==24 &
Filename=="v2msa8"))

The name of the dataframe / variable of an individual trial can be
obtained using:
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
Then I get a string:
"t24v2msa8.gz"
which is of the exact same name of the dataframe / variable of that
trial, which is:
t24v2msa8.gz

Can somebody tell me how can I change that string (obtained from
"paste()" above) to be a usable / manipulable variable name, so that I
can do something, such as:
(1)
tmptrial <- trialcompute(trialextract(
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
,tmptrialinfo[1,32],secs,sdm),secs,binsize)
instead of hardcoding:
(2)
tmptrial <-
trialcompute(trialextract(t24v2msa8.gz,tmptrialinfo[1,32],secs,sdm),secs,binsize)

Currently, 1) doesn't work...

Thanks in advance for your help!

Regards,

      John

On Dec 8, 2008, at 10:11 AM, tsunhin wong wrote:
> Dear all,
>
> I'm a newbie in R.
> I have a 45x2x2x8 design.
> A dataframe stores the metadata of trials. And each trial has its own
> data file: I used "read.table" to import every trial into R as a
> dataframe (variable).
>
> Now I dynamically ask R to retrieve trials that fit certain selection
> criteria, so I use "subset", e.g.
> tmptrialinfo <- subset(trialinfo, (Subject==24 &
Filename=="v2msa8"))
>
> The name of the dataframe / variable of an individual trial can be
> obtained using:
>
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
> Then I get a string:
> "t24v2msa8.gz"
> which is of the exact same name of the dataframe / variable of that
> trial, which is:
> t24v2msa8.gz
>
> Can somebody tell me how can I change that string (obtained from
> "paste()" above) to be a usable / manipulable variable name, so
that I
> can do something, such as:
> (1)
> tmptrial <- trialcompute(trialextract(
>
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
> ,tmptrialinfo[1,32],secs,sdm),secs,binsize)
> instead of hardcoding:
> (2)
> tmptrial <-  
> trialcompute 
> (trialextract(t24v2msa8.gz,tmptrialinfo[1,32],secs,sdm),secs,binsize)
>
It may have something to do with the semantics of trialextract about  
which most useRs will know nothing (and I was unsuccessful in finding  
a function by that name with an Rsitesearch). It seems strange that a  
function would accept an unquoted reference to what is obviously a  
file name. Perhaps you should be offering that code for inspection  
rather than asking how to make a simple assignment. It is possible  
that what you are really asking is answered by Faq 7.21:

http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-turn-a-string-into-a-variable_003f
> Currently, 1) doesn't work...
Saying "doesn't work" is not specific enough. What exactly was the
error message?
>
>
> Thanks in advance for your help!
>
> Regards,
>
>      John
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

?get


Sent from my iPhone

On Dec 8, 2008, at 7:11, "tsunhin wong" <thjwong at gmail.com>
wrote:
> Dear all,
>
> I'm a newbie in R.
> I have a 45x2x2x8 design.
> A dataframe stores the metadata of trials. And each trial has its own
> data file: I used "read.table" to import every trial into R as a
> dataframe (variable).
>
> Now I dynamically ask R to retrieve trials that fit certain selection
> criteria, so I use "subset", e.g.
> tmptrialinfo <- subset(trialinfo, (Subject==24 &
Filename=="v2msa8"))
>
> The name of the dataframe / variable of an individual trial can be
> obtained using:
>
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
> Then I get a string:
> "t24v2msa8.gz"
> which is of the exact same name of the dataframe / variable of that
> trial, which is:
> t24v2msa8.gz
>
> Can somebody tell me how can I change that string (obtained from
> "paste()" above) to be a usable / manipulable variable name, so
that I
> can do something, such as:
> (1)
> tmptrial <- trialcompute(trialextract(
>
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
> ,tmptrialinfo[1,32],secs,sdm),secs,binsize)
> instead of hardcoding:
> (2)
> tmptrial <-  
> trialcompute( 
> trialextract(t24v2msa8.gz,tmptrialinfo[1,32],secs,sdm),secs,binsize)
>
> Currently, 1) doesn't work...
>
> Thanks in advance for your help!
>
> Regards,
>
>      John
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

Dear Tsunhin,
Take a look at ?get

HTH,

Jorge


On Mon, Dec 8, 2008 at 10:11 AM, tsunhin wong <thjwong@gmail.com> wrote:
> Dear all,
>
> I'm a newbie in R.
> I have a 45x2x2x8 design.
> A dataframe stores the metadata of trials. And each trial has its own
> data file: I used "read.table" to import every trial into R as a
> dataframe (variable).
>
> Now I dynamically ask R to retrieve trials that fit certain selection
> criteria, so I use "subset", e.g.
> tmptrialinfo <- subset(trialinfo, (Subject==24 &
Filename=="v2msa8"))
>
> The name of the dataframe / variable of an individual trial can be
> obtained using:
>
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
> Then I get a string:
> "t24v2msa8.gz"
> which is of the exact same name of the dataframe / variable of that
> trial, which is:
> t24v2msa8.gz
>
> Can somebody tell me how can I change that string (obtained from
> "paste()" above) to be a usable / manipulable variable name, so
that I
> can do something, such as:
> (1)
> tmptrial <- trialcompute(trialextract(
>
paste("t",tmptrialinfo[1,2],tmptrialinfo[1,16],".gz",sep="")
> ,tmptrialinfo[1,32],secs,sdm),secs,binsize)
> instead of hardcoding:
> (2)
> tmptrial <-
>
trialcompute(trialextract(t24v2msa8.gz,tmptrialinfo[1,32],secs,sdm),secs,binsize)
>
> Currently, 1) doesn't work...
>
> Thanks in advance for your help!
>
> Regards,
>
>      John
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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