on 06/21/2008 09:19 PM milton ruser wrote:> Hi there,
>
> I have a list of filenames like
>
> a<-c("file1.dbf", "file32.dbf",
"myfile_temp.dbf")
>
> and I would like to remove the ".dbf" string from all records and
obtain
> somethink like
>
> file1
> file32
> myfile_temp
>
> Thanks in advance,
>
> miltinho
> brazil
As is usually the case with R, there are several approaches:
> sub("\\.dbf", "", a)
[1] "file1" "file32" "myfile_temp"
> sapply(strsplit(a, "\\."), "[", 1)
[1] "file1" "file32" "myfile_temp"
> substr(a, 1, nchar(a) - 4)
[1] "file1" "file32" "myfile_temp"
My personal preference would be the first.
See ?sub, ?strsplit, ?sapply, ?substr and ?nchar for more information.
As an aside, if you should need to manipulate complete file paths to
extract the file name, see ?basename
HTH,
Marc Schwartz