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You just need to return the values computed when a==0 and when a!=0. a=0 f=function(x,y,z=0) { if (a==0) return(x[1]+x[2]+y) if (a!=0) return(x[1]+x[2]+y+z) }> f(1:2,3)[1] 6>Ravi. ---------------------------------------------------------------------------- ------- Ravi Varadhan, Ph.D. Assistant Professor, The Center on Aging and Health Division of Geriatric Medicine and Gerontology Johns Hopkins University Ph: (410) 502-2619 Fax: (410) 614-9625 Email: rvaradhan at jhmi.edu Webpage: http://www.jhsph.edu/agingandhealth/People/Faculty/Varadhan.html ---------------------------------------------------------------------------- -------- -----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Dwayne Blind Sent: Wednesday, March 12, 2008 1:59 PM To: r-help at r-project.org Subject: [R] default values Dear R users, I wrote the following toy example to explain my problem : a=0 f=function(x,y,z) { if (a==0) x[1]+x[2]+y if (a!=0) x[1]+x[2]+y+z } f(1:2,3) I have not specified z and I get an error. Although a=0, R seems to want to know z because it's in the expression x[1]+x[2]+y+z. So I tried to put a default value : a=0 f=function(x,y,z=0) { if (a==0) x[1]+x[2]+y if (a!=0) x[1]+x[2]+y+z } f(1:2,3) Why isn't it working ? Sometimes everything is fine even though a parameter is not specified. Thanks a lot. [[alternative HTML version deleted]] ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
On Wed, 12 Mar 2008, Dwayne Blind wrote:> Dear R users, > > I wrote the following toy example to explain my problem : > > a=0 > f=function(x,y,z) { > if (a==0) x[1]+x[2]+y > if (a!=0) x[1]+x[2]+y+z > } > f(1:2,3) > > > I have not specified z and I get an error.What was the error? It works for me (so I've no idea), and returns NULL, the value of the last expression (invisibly). I think you intended f <- function(x, y, z) if (a==0) x[1]+x[2]+y else x[1]+x[2]+y+z or f <- function(x, y, z) ifelse(a==0, x[1]+x[2]+y, x[1]+x[2]+y+z)> Although a=0, R seems to want to > know z because it's in the expression x[1]+x[2]+y+z. > > So I tried to put a default value : > > a=0 > f=function(x,y,z=0) { > if (a==0) x[1]+x[2]+y > if (a!=0) x[1]+x[2]+y+z > } > f(1:2,3) > > Why isn't it working ? Sometimes everything is fine even though a parameter > is not specified. > > Thanks a lot. > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Brian D. Ripley, ripley at stats.ox.ac.uk Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595