R help - Mar 2005 - KNN one factor predicting problem

Could anybody help me out please?
> cl<-as.factor(traindata[,13])
> knn(traindata[1:295,2], newdata[1:32,2], cl,k=2,
prob=TRUE) 
Error in knn(traindata[1:295, 2], newdata[1:32, 2],
cl, k = m, prob = TRUE) : 
        Dims of test and train differ

Both traindata and newdata have 13 elements. Only one
of the first 12 elemnets is needed to predict the 13
element.
What's the problem of following commands?

Thank you very much indeed

Qin

> From: liu qin
> 
> Could anybody help me out please?
> 
> > cl<-as.factor(traindata[,13])
> > knn(traindata[1:295,2], newdata[1:32,2], cl,k=2,
> prob=TRUE) 
> Error in knn(traindata[1:295, 2], newdata[1:32, 2],
> cl, k = m, prob = TRUE) : 
>         Dims of test and train differ
> 
> Both traindata and newdata have 13 elements. Only one
> of the first 12 elemnets is needed to predict the 13
> element.
> What's the problem of following commands?
`traindata[1:295, 2]' says to use the first 295 rows of the second column of
traindata, and likewise you specified the first 32 rows of the second column
of newdata as the second argument.  What do you mean by 12 elements?

Andy

 
> Thank you very much indeed
> 
> Qin
> 
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