Dear R users: I have some difficulties analizing data with mixed effects NLME and the last version of R. More concretely, I have a repeated measures design with a single group and 2 experimental factors (say A and B) and my interest is to compare additive and nonadditive models. suj rv A B 1 s1 4 a1 b1 2 s1 5 a1 b2 3 s1 7 a1 b3 4 s1 1 a2 b1 5 s1 4 a2 b2 6 s1 2 a2 b3 7 s2 6 a1 b1 8 s2 8 a1 b2 9 s2 10 a1 b3 10 s2 3 a2 b1 11 s2 6 a2 b2 12 s2 6 a2 b3 13 s3 1 a1 b1 14 s3 6 a1 b2 15 s3 5 a1 b3 16 s3 3 a2 b1 17 s3 5 a2 b2 18 s3 4 a2 b3 19 s4 2 a1 b1 20 s4 10 a1 b2 21 s4 12 a1 b3 22 s4 1 a2 b1 23 s4 4 a2 b2 24 s4 7 a2 b3 25 s5 5 a1 b1 26 s5 10 a1 b2 27 s5 10 a1 b3 28 s5 5 a2 b1 29 s5 6 a2 b2 30 s5 5 a2 b3 31 s6 1 a1 b1 32 s6 7 a1 b2 33 s6 8 a1 b3 34 s6 2 a2 b1 35 s6 8 a2 b2 36 s6 7 a2 b3 It is very easy to fit these data with base R function AOV: NonAdditive model: aov(rv ~ A*B + Error(suj+suj/A+suj/B) Additive model: aov(rv ~ A*B + Error(suj) and also easy with SAS MIXED (I missed some obvious lines): NonAdditive model model vr = A B A*B; random suj A*suj B*suj; repeated / type=cs subj=suj; Additive model; model vr = A B A*B /ddfm=satterth; repeated / type=cs subj=suj; Using LME I do not find any problems to fit the additive model with lme(vr~A*B, random=~1|suj, cor=corCompSymm()) but I have found some difficulties fitting the nonadditive model. Can anyone help me? Thanks in advance. Manuel Ato Dpto. Psic.B?sica y Metodolog?a Apartado 4021 30080 MURCIA (Spain) e-mail: matogar at um.es
1. Have you reviewed Pinhiero and Bates (2000) Mixed Effects Models in S and S-Plus (Springer)? I think the answer is there. 2. Observing the philosophy that a quick response that may contain an error is often better than a perfect but late response, I will offer a suggestion I have not checked: Have you considered "random = ~1+A+B|subj"? hope this helps. spencer graves Manuel Ato Garcia wrote:>Dear R users: > > I have some difficulties analizing data with mixed effects NLME and the >last version of R. More concretely, I have a repeated measures design with >a single group and 2 experimental factors (say A and B) and my interest is >to compare additive and nonadditive models. > > suj rv A B >1 s1 4 a1 b1 >2 s1 5 a1 b2 >3 s1 7 a1 b3 >4 s1 1 a2 b1 >5 s1 4 a2 b2 >6 s1 2 a2 b3 >7 s2 6 a1 b1 >8 s2 8 a1 b2 >9 s2 10 a1 b3 >10 s2 3 a2 b1 >11 s2 6 a2 b2 >12 s2 6 a2 b3 >13 s3 1 a1 b1 >14 s3 6 a1 b2 >15 s3 5 a1 b3 >16 s3 3 a2 b1 >17 s3 5 a2 b2 >18 s3 4 a2 b3 >19 s4 2 a1 b1 >20 s4 10 a1 b2 >21 s4 12 a1 b3 >22 s4 1 a2 b1 >23 s4 4 a2 b2 >24 s4 7 a2 b3 >25 s5 5 a1 b1 >26 s5 10 a1 b2 >27 s5 10 a1 b3 >28 s5 5 a2 b1 >29 s5 6 a2 b2 >30 s5 5 a2 b3 >31 s6 1 a1 b1 >32 s6 7 a1 b2 >33 s6 8 a1 b3 >34 s6 2 a2 b1 >35 s6 8 a2 b2 >36 s6 7 a2 b3 > >It is very easy to fit these data with base R function AOV: > >NonAdditive model: > aov(rv ~ A*B + Error(suj+suj/A+suj/B) > >Additive model: > aov(rv ~ A*B + Error(suj) > >and also easy with SAS MIXED (I missed some obvious lines): > >NonAdditive model > model vr = A B A*B; > random suj A*suj B*suj; > repeated / type=cs subj=suj; > >Additive model; > model vr = A B A*B /ddfm=satterth; > repeated / type=cs subj=suj; > >Using LME I do not find any problems to fit the additive model with > > lme(vr~A*B, random=~1|suj, cor=corCompSymm()) > >but I have found some difficulties fitting the nonadditive model. > > Can anyone help me? > > Thanks in advance. > > Manuel Ato > Dpto. Psic.B?sica y Metodolog?a > Apartado 4021 > 30080 MURCIA (Spain) > e-mail: matogar at um.es > >______________________________________________ >R-help at stat.math.ethz.ch mailing list >https://www.stat.math.ethz.ch/mailman/listinfo/r-help > >
Hi, R-users: Last week I send a request for help to this list. I have receive until now two kindly responses from Spencer Graves and Renauld Lancelot. They both point interesting things to fit an adequate model to my data but unfortunately it persists without a satisfactory solution. I propose again the same problem but using with a different dataset (Assay), taken from Pinheiro and Bates' book on page 163, that is relevant with crossed random effects. I have fitted the same model (p. 165)>fmAssay <- lme(logDens ~ sample * dilut, Assay, random=pdBlocked(list(,pdIdent(~1), pdIdent(~sample-1),pdIdent(~dilut-1))) ) and the results with "anova" function (p. 166) are numDF denDF F-value p-value (Intercept) 1 29 537.6294 <.0001 sample 5 29 11.2103 <.0001 dilut 4 29 420.5458 <.0001 sample:dilut 20 29 1.6072 0.1192 The problem is that with this approach one obtains correct F-values, but using a common residual term for DenDF that is a combination of (Block + Block:sample + Block:dilut). Then probability values are different to that obtained when we used the classical AOV funtion to fit the same model, because in this case each term is mapped with a error term (so "sample" uses "Block:sample", "dilut" uses "Block:dilut", and "sample:dilut" uses "Block:sample:dilut"):>mod<-aov(logDens ~ sample*dilut + Error(Block+Block/sample+Block/dilut),data=Assay)>summary(mod)Error: Block Df Sum Sq Mean Sq F value Pr(>F) Residuals 1 0.0083115 0.0083115 Error: Block:sample Df Sum Sq Mean Sq F value Pr(>F) sample 5 0.276153 0.055231 11.213 0.009522 Residuals 5 0.024627 0.004925 Error: Block:dilut Df Sum Sq Mean Sq F value Pr(>F) dilut 4 3.7491 0.9373 420.79 1.684e-05 Residuals 4 0.0089 0.0022 Error: Within Df Sum Sq Mean Sq F value Pr(>F) sample:dilut 20 0.055525 0.002776 1.6069 0.1486 Residuals 20 0.034555 0.001728 Obviously, the interest on linear mixed effects is open with the possibility of modeling with correlated and/or heterocedastic errors, and this end cannot be pursued with AOV function. Summarizing, the problem is that I have not found a way to obtain with NLME the same results (DF, F-ratios and probabilities) that I get with AOV and multistratum errors. Is this an inconvenience of program?, probably due to the impossibility to use multiple nested arguments as random(~1|Block/sample+dilut) or random(~1|Block/sample*dilut) SAS MIXED can also fit these data and obtain correct results by means of a combination of "random" and "repeated" arguments: model = sample dilut sample*dilut; random = Block sample*Block dilut*Block; repeated /type=cs Sub=Block; Type 3 Tests of Fixed Effects Num Den Effect DF DF F Value Pr > F sample 5 5 11.21 0.0095 dilut 4 4 420.79 <.0001 sample*dilut 20 20 1.61 0.1486 May be possible obtain the same results with NLME function? I would appreciate any kind of help. Best regards, Manuel Ato University of Murcia Spain e-mail: matogar at um.es
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