R help - Dec 2001 - conflicting results on NA in a qda predicted object:

Dear list,

(I've not upgraded to R1.4 yet)

I have the following $class component in a predict.qda
object:
> unique(mod23S.qda.pred$class)
 [1] 12 17 8  10 4  9  5  13 14 19 20 15 6  3  7  1  23 11 18 21 16 2  22 NA
Levels:  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23

Nevertheless, when I try to identify the individual(s) with NA, I
get:
> any(is.na(mod23S.qda.pred$class))
[1] FALSE

and
> mod23S.qda.pred$class[is.na(mod23S.qda.pred$class)]
factor(0)
Levels:  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 

So, actually, is there a NA value in mod23S.qda.pred$class or not?

(screening by eye it`s impossible:
length(mod23S.qda.pred$class) is 26375 )

Agus

Dr. Agustin Lobo
Instituto de Ciencias de la Tierra (CSIC)
Lluis Sole Sabaris s/n
08028 Barcelona SPAIN
tel 34 93409 5410
fax 34 93411 0012
alobo at ija.csic.es



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This is a factor.  You have to be careful with NAs in factors (and 1.4.0
is different there as it happens).

Nevertheless, there is no way to reproduce this from what you have given.
Check that the class really is "factor", and then unclass it to see
what
the codes actually are.  One or more of them should be NA from what you
have given.


On Thu, 20 Dec 2001, Agustin Lobo wrote:
>
> Dear list,
>
> (I've not upgraded to R1.4 yet)
>
> I have the following $class component in a predict.qda object:
> > unique(mod23S.qda.pred$class)
>  [1] 12 17 8  10 4  9  5  13 14 19 20 15 6  3  7  1  23 11 18 21 16 2  22
NA
> Levels:  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23
>
> Nevertheless, when I try to identify the individual(s) with NA, I get:
> > any(is.na(mod23S.qda.pred$class))
> [1] FALSE
>
> and
>
> > mod23S.qda.pred$class[is.na(mod23S.qda.pred$class)]
> factor(0)
> Levels:  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23
>
> So, actually, is there a NA value in mod23S.qda.pred$class or not?
>
> (screening by eye it`s impossible:
> length(mod23S.qda.pred$class) is 26375 )
>
> Agus
>
> Dr. Agustin Lobo
> Instituto de Ciencias de la Tierra (CSIC)
> Lluis Sole Sabaris s/n
> 08028 Barcelona SPAIN
> tel 34 93409 5410
> fax 34 93411 0012
> alobo at ija.csic.es
>
>
>
>
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-- 
Brian D. Ripley,                  ripley at stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272860 (secr)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595

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Hello,

I use function "svm" (interface to libsvm) from package e1071. It
works just
fine.
And I may predict with function "predict" and svm model trained by
function
"svm".
What I need is moving results of svm training to another application (non-R)
and
perform prediction there. But function "svm" returns list of support
vectors
only
and doesn't return coefficients of separating hyperplane (w).

So, the question is how to use results of svm training to write (in other
language)
prediction function for linear and nonlinear cases?

Thanks,
Alexander.

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Hmm, if you tell us WHAT KIND OF TROUBLES you experience it might be
easier for us to help you ...

fritz
>>>>> On Thu, 20 Dec 2001 08:11:00 -0600,
>>>>> Kenneth Cabrera (KC) wrote:
  > Hello dear R fans!
  > I got a trouble with update.packages() with the version 1.4.0 on
  > windows 2000.

  > I make already the change in ..\modules directory.

  > I rename internet.dll to internetold.dll and I
  > rename   internet2.dll to internet.dll

  > My internet conexion has a proxy.

  > In the version 1.3.1 works everything fine!

  > Thank you for your help.

  > Kenneth

  > P.S. I download the a precompiled version of R 1.4.0 for windows from

  > http://www.stats.ox.ac.uk/pub/bdr/RWin/Rpre/rw1040*.zip



  >
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  >
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Hello dear R fans!

I got a trouble with update.packages() with the version 1.4.0 on
windows 2000.

I make already the change in ..\modules directory.

I rename internet.dll to internetold.dll and I
rename   internet2.dll to internet.dll

My internet conexion has a proxy.

In the version 1.3.1 works everything fine!

Thank you for your help.

Kenneth

P.S. I download the a precompiled version of R 1.4.0 for windows from

http://www.stats.ox.ac.uk/pub/bdr/RWin/Rpre/rw1040*.zip



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