Hi, This is the input data frame: ############################################### df.1 = read.table(header=T,text=" id gender WMC_alcohol WMC_caffeine WMC_no.drug RT_alcohol RT_caffeine RT_no.drug 1 1 female 3.7 3.7 3.9 488 236 371 2 2 female 6.4 7.3 7.9 607 376 349 3 3 female 4.6 7.4 7.3 643 226 412 4 4 male 6.4 7.8 8.2 684 206 252 5 5 female 4.9 5.2 7.0 593 262 439 6 6 male 5.4 6.6 7.2 492 230 464 7 7 male 7.9 7.9 8.9 690 259 327 8 8 male 4.1 5.9 4.5 486 230 305 9 9 female 5.2 6.2 7.2 686 273 327 10 10 female 6.2 7.4 7.8 645 240 498 ") ############################################### This is the desired output: ############################################### id gender drug WMC RT 1 1 female alcohol 3.7 488 2 2 female alcohol 6.4 607 3 3 female alcohol 4.6 643 4 4 male alcohol 6.4 684 5 5 female alcohol 4.9 593 6 6 male alcohol 5.4 492 7 7 male alcohol 7.9 690 8 8 male alcohol 4.1 486 9 9 female alcohol 5.2 686 10 10 female alcohol 6.2 645 11 1 female caffeine 3.7 236 12 2 female caffeine 7.3 376 ############################################### I know some melt and cast magic is required. But I was unable to sort it myself. Here are the dput versions: Input Data Frame ###############################################> dput(df.1)structure(list(id = 1:10, gender = structure(c(1L, 1L, 1L, 2L, 1L, 2L, 2L, 2L, 1L, 1L), .Label = c("female", "male"), class = "factor"), WMC_alcohol = c(3.7, 6.4, 4.6, 6.4, 4.9, 5.4, 7.9, 4.1, 5.2, 6.2), WMC_caffeine = c(3.7, 7.3, 7.4, 7.8, 5.2, 6.6, 7.9, 5.9, 6.2, 7.4), WMC_no.drug = c(3.9, 7.9, 7.3, 8.2, 7, 7.2, 8.9, 4.5, 7.2, 7.8), RT_alcohol = c(488L, 607L, 643L, 684L, 593L, 492L, 690L, 486L, 686L, 645L), RT_caffeine = c(236L, 376L, 226L, 206L, 262L, 230L, 259L, 230L, 273L, 240L), RT_no.drug c(371L, 349L, 412L, 252L, 439L, 464L, 327L, 305L, 327L, 498L)), .Names c("id", "gender", "WMC_alcohol", "WMC_caffeine", "WMC_no.drug", "RT_alcohol", "RT_caffeine", "RT_no.drug"), class = "data.frame", row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10")) Output Data Frame ###############################################> dput(df.output)structure(list(id = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 1L, 2L), gender = structure(c(1L, 1L, 1L, 2L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 1L), .Label = c("female", "male"), class = "factor"), drug = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L), .Label = c("alcohol", "caffeine"), class = "factor"), WMC = c(3.7, 6.4, 4.6, 6.4, 4.9, 5.4, 7.9, 4.1, 5.2, 6.2, 3.7, 7.3), RT = c(488L, 607L, 643L, 684L, 593L, 492L, 690L, 486L, 686L, 645L, 236L, 376L)), .Names = c("id", "gender", "drug", "WMC", "RT"), class = "data.frame", row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12")) Cheers ! [[alternative HTML version deleted]]
I see your desired output has rather fewer data than the input data frame. Instead of making us pore over a bunch of numbers, can you explain exactly what filtering you wish to do to get the specific subset of {male/female} {alcohol/caffeine} you're trying to get? BHM wrote> Hi, > > This is the input data frame: > > ############################################### > df.1 = read.table(header=T,text=" > id gender WMC_alcohol WMC_caffeine WMC_no.drug RT_alcohol RT_caffeine > RT_no.drug > 1 1 female 3.7 3.7 3.9 488 236 371 > 2 2 female 6.4 7.3 7.9 607 376 349 > 3 3 female 4.6 7.4 7.3 643 226 412 > 4 4 male 6.4 7.8 8.2 684 206 252 > 5 5 female 4.9 5.2 7.0 593 262 439 > 6 6 male 5.4 6.6 7.2 492 230 464 > 7 7 male 7.9 7.9 8.9 690 259 327 > 8 8 male 4.1 5.9 4.5 486 230 305 > 9 9 female 5.2 6.2 7.2 686 273 327 > 10 10 female 6.2 7.4 7.8 645 240 498 > ") > ############################################### > > This is the desired output: > ############################################### > id gender drug WMC RT > 1 1 female alcohol 3.7 488 > 2 2 female alcohol 6.4 607 > 3 3 female alcohol 4.6 643 > 4 4 male alcohol 6.4 684 > 5 5 female alcohol 4.9 593 > 6 6 male alcohol 5.4 492 > 7 7 male alcohol 7.9 690 > 8 8 male alcohol 4.1 486 > 9 9 female alcohol 5.2 686 > 10 10 female alcohol 6.2 645 > 11 1 female caffeine 3.7 236 > 12 2 female caffeine 7.3 376 > ############################################### > > I know some melt and cast magic is required. But I was unable to sort it > myself. > > Here are the dput versions: > > Input Data Frame > ############################################### >> dput(df.1) > structure(list(id = 1:10, gender = structure(c(1L, 1L, 1L, 2L, > 1L, 2L, 2L, 2L, 1L, 1L), .Label = c("female", "male"), class = "factor"), > WMC_alcohol = c(3.7, 6.4, 4.6, 6.4, 4.9, 5.4, 7.9, 4.1, 5.2, > 6.2), WMC_caffeine = c(3.7, 7.3, 7.4, 7.8, 5.2, 6.6, 7.9, > 5.9, 6.2, 7.4), WMC_no.drug = c(3.9, 7.9, 7.3, 8.2, 7, 7.2, > 8.9, 4.5, 7.2, 7.8), RT_alcohol = c(488L, 607L, 643L, 684L, > 593L, 492L, 690L, 486L, 686L, 645L), RT_caffeine = c(236L, > 376L, 226L, 206L, 262L, 230L, 259L, 230L, 273L, 240L), RT_no.drug > c(371L, > 349L, 412L, 252L, 439L, 464L, 327L, 305L, 327L, 498L)), .Names > c("id", > "gender", "WMC_alcohol", "WMC_caffeine", "WMC_no.drug", "RT_alcohol", > "RT_caffeine", "RT_no.drug"), class = "data.frame", row.names = c("1", > "2", "3", "4", "5", "6", "7", "8", "9", "10")) > > > Output Data Frame > ############################################### >> dput(df.output) > structure(list(id = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, > 1L, 2L), gender = structure(c(1L, 1L, 1L, 2L, 1L, 2L, 2L, 2L, > 1L, 1L, 1L, 1L), .Label = c("female", "male"), class = "factor"), > drug = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, > 2L, 2L), .Label = c("alcohol", "caffeine"), class = "factor"), > WMC = c(3.7, 6.4, 4.6, 6.4, 4.9, 5.4, 7.9, 4.1, 5.2, 6.2, > 3.7, 7.3), RT = c(488L, 607L, 643L, 684L, 593L, 492L, 690L, > 486L, 686L, 645L, 236L, 376L)), .Names = c("id", "gender", > "drug", "WMC", "RT"), class = "data.frame", row.names = c("1", > "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12")) > > > Cheers ! > > [[alternative HTML version deleted]] > > ______________________________________________> R-help@> mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.-- View this message in context: http://r.789695.n4.nabble.com/Help-with-Cast-Function-tp4681381p4681384.html Sent from the R help mailing list archive at Nabble.com.
On Nov 29, 2013, at 9:42 AM, Burhan ul haq wrote:> Hi, > > This is the input data frame: > > ############################################### > df.1 = read.table(header=T,text=" > id gender WMC_alcohol WMC_caffeine WMC_no.drug RT_alcohol RT_caffeine > RT_no.drug > 1 1 female 3.7 3.7 3.9 488 236 371 > 2 2 female 6.4 7.3 7.9 607 376 349 > 3 3 female 4.6 7.4 7.3 643 226 412 > 4 4 male 6.4 7.8 8.2 684 206 252 > 5 5 female 4.9 5.2 7.0 593 262 439 > 6 6 male 5.4 6.6 7.2 492 230 464 > 7 7 male 7.9 7.9 8.9 690 259 327 > 8 8 male 4.1 5.9 4.5 486 230 305 > 9 9 female 5.2 6.2 7.2 686 273 327 > 10 10 female 6.2 7.4 7.8 645 240 498 > ") > ############################################### > > This is the desired output: > ############################################### > id gender drug WMC RT > 1 1 female alcohol 3.7 488 > 2 2 female alcohol 6.4 607 > 3 3 female alcohol 4.6 643 > 4 4 male alcohol 6.4 684 > 5 5 female alcohol 4.9 593 > 6 6 male alcohol 5.4 492 > 7 7 male alcohol 7.9 690 > 8 8 male alcohol 4.1 486 > 9 9 female alcohol 5.2 686 > 10 10 female alcohol 6.2 645 > 11 1 female caffeine 3.7 236 > 12 2 female caffeine 7.3 376 > ############################################### > > I know some melt and cast magic is required. But I was unable to sort it > myself. ># this is base::reshape reshape(df.1, idvar=1:2, sep="_", direction="long", varying=names(df.1)[3:8])> Here are the dput versions: > > Input Data Frame > ############################################### >> dput(df.1) > structure(list(id = 1:10, gender = structure(c(1L, 1L, 1L, 2L, > 1L, 2L, 2L, 2L, 1L, 1L), .Label = c("female", "male"), class = "factor"), > WMC_alcohol = c(3.7, 6.4, 4.6, 6.4, 4.9, 5.4, 7.9, 4.1, 5.2, > 6.2), WMC_caffeine = c(3.7, 7.3, 7.4, 7.8, 5.2, 6.6, 7.9, > 5.9, 6.2, 7.4), WMC_no.drug = c(3.9, 7.9, 7.3, 8.2, 7, 7.2, > 8.9, 4.5, 7.2, 7.8), RT_alcohol = c(488L, 607L, 643L, 684L, > 593L, 492L, 690L, 486L, 686L, 645L), RT_caffeine = c(236L, > 376L, 226L, 206L, 262L, 230L, 259L, 230L, 273L, 240L), RT_no.drug > c(371L, > 349L, 412L, 252L, 439L, 464L, 327L, 305L, 327L, 498L)), .Names > c("id", > "gender", "WMC_alcohol", "WMC_caffeine", "WMC_no.drug", "RT_alcohol", > "RT_caffeine", "RT_no.drug"), class = "data.frame", row.names = c("1", > "2", "3", "4", "5", "6", "7", "8", "9", "10")) > > > Output Data Frame > ############################################### >> dput(df.output) > structure(list(id = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, > 1L, 2L), gender = structure(c(1L, 1L, 1L, 2L, 1L, 2L, 2L, 2L, > 1L, 1L, 1L, 1L), .Label = c("female", "male"), class = "factor"), > drug = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, > 2L, 2L), .Label = c("alcohol", "caffeine"), class = "factor"), > WMC = c(3.7, 6.4, 4.6, 6.4, 4.9, 5.4, 7.9, 4.1, 5.2, 6.2, > 3.7, 7.3), RT = c(488L, 607L, 643L, 684L, 593L, 492L, 690L, > 486L, 686L, 645L, 236L, 376L)), .Names = c("id", "gender", > "drug", "WMC", "RT"), class = "data.frame", row.names = c("1", > "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12")) > > > Cheers ! > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.David Winsemius Alameda, CA, USA