1) Use dput() to submit data.
2) Would this work? (It requires your data are evenly spaced, but I
think that's it) d[seq(1, nrow(d), by = 3), ]
Michael
On Wed, Dec 14, 2011 at 7:17 AM, abcdef ghijk <linehunk at yahoo.com>
wrote:> ?Good Morning ,
>
> I want to sample the following time series for every third hour. For
example at 00:00,03:00,06:00,09:00 etc.
>
>
> 2011-01-01 00:00:00 0.000000e+00
> 2011-01-01 01:00:00 1.471667e+01
> 2011-01-01 02:00:00 1.576667e+01
> 2011-01-01 03:00:00 0.000000e+00
> 2011-01-01 04:00:00 0.000000e+00
> 2011-01-01 05:00:00 0.000000e+00
> 2011-01-01 06:00:00 0.000000e+00
> 2011-01-01 07:00:00 0.000000e+00
> 2011-01-01 08:00:00 0.000000e+00
> 2011-01-01 09:00:00 1.826667e+01
> 2011-01-01 10:00:00 0.000000e+00
> 2011-01-01 11:00:00 0.000000e+00
> 2011-01-01 12:00:00 0.000000e+00
> 2011-01-01 13:00:00 0.000000e+00
> 2011-01-01 14:00:00 0.000000e+00
> 2011-01-01 15:00:00 0.000000e+00
> 2011-01-01 16:00:00 0.000000e+00
> 2011-01-01 17:00:00 0.000000e+00
> 2011-01-01 18:00:00 0.000000e+00
> 2011-01-01 19:00:00 0.000000e+00
> 2011-01-01 20:00:00 0.000000e+00
> 2011-01-01 21:00:00 7.010000e+01
> 2011-01-01 22:00:00 7.154167e+02
> 2011-01-01 23:00:00 2.039167e+02
> 2011-01-02 00:00:00 3.703000e+02
> 2011-01-02 01:00:00 9.130167e+02
> 2011-01-02 02:00:00 0.000000e+00
> 2011-01-02 03:00:00 0.000000e+00
> Thanks in advance.
> Regards,
> Shan
>
> ? ? ? ?[[alternative HTML version deleted]]
>
>
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