Dear all, I would like to search in a string for the second occurrence of a symbol and replace the symbol after it For example my strings look like sta_+1+0_field2ndtry_0000$01.cfg I want to find the digit that comes after the second +, in that case is zero and then over a loop create the strings below sta_+1+0_field2ndtry_0000$01.cfg sta_+1+1_field2ndtry_0000$01.cfg sta_+1+2_field2ndtry_0000$01.cfg sta_+1+3_field2ndtry_0000$01.cfg and so on.. I have already tried strsplit but this will make things more complex... Could you please help me with that? B.R Alex [[alternative HTML version deleted]]
try this:> x <- c('sta_+1+0_field2ndtry_0000$01.cfg'+ , 'sta_+1+0_field2ndtry_0000$01.cfg' + , 'sta_+1-0_field2ndtry_0000$01.cfg' + , 'sta_+1+0_field2ndtry_0000$01.cfg' + )> # find matching fields > values <- grep("[^+]*\\+[^+]*\\+0", x, value = TRUE) > # split into two pieces > splitValues <- sub("([^+]*\\+[^+]*\\+)0(.*)", "\\1^\\2", values) > for (i in splitValues){+ for (j in 0:3){ + print(sub("\\^", j, i)) + } + } [1] "sta_+1+0_field2ndtry_0000$01.cfg" [1] "sta_+1+1_field2ndtry_0000$01.cfg" [1] "sta_+1+2_field2ndtry_0000$01.cfg" [1] "sta_+1+3_field2ndtry_0000$01.cfg" [1] "sta_+1+0_field2ndtry_0000$01.cfg" [1] "sta_+1+1_field2ndtry_0000$01.cfg" [1] "sta_+1+2_field2ndtry_0000$01.cfg" [1] "sta_+1+3_field2ndtry_0000$01.cfg" [1] "sta_+1+0_field2ndtry_0000$01.cfg" [1] "sta_+1+1_field2ndtry_0000$01.cfg" [1] "sta_+1+2_field2ndtry_0000$01.cfg" [1] "sta_+1+3_field2ndtry_0000$01.cfg" On Fri, Dec 2, 2011 at 6:30 AM, Alaios <alaios at yahoo.com> wrote:> Dear all, > I would like to search in a string for the second occurrence of a symbol and replace the symbol after it > > For example my strings look like > > sta_+1+0_field2ndtry_0000$01.cfg > > I want to find the digit that comes after the second +, in that case is zero > and then over a loop create the strings below > > sta_+1+0_field2ndtry_0000$01.cfg > > sta_+1+1_field2ndtry_0000$01.cfg > > sta_+1+2_field2ndtry_0000$01.cfg > > sta_+1+3_field2ndtry_0000$01.cfg > > and so on.. > I have already tried strsplit but this will make things more complex... > > Could you please help me with that? > > B.R > Alex > > ? ? ? ?[[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.-- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it.
If the length of the fists part is constant (the "sta_+1+" part) the you can use substr() On 2 December 2011 13:30, Alaios <alaios at yahoo.com> wrote:>Dear all,> I would like to search in a string for the second occurrence of a symbol and replace the symbol after it > > For example my strings look like > > sta_+1+0_field2ndtry_0000$01.cfg > > I want to find the digit that comes after the second +, in that case is zero > and then over a loop create the strings below > > sta_+1+0_field2ndtry_0000$01.cfg > > sta_+1+1_field2ndtry_0000$01.cfg > > sta_+1+2_field2ndtry_0000$01.cfg > > sta_+1+3_field2ndtry_0000$01.cfg > > and so on.. > I have already tried strsplit but this will make things more complex... > > Could you please help me with that? > > B.R > Alex >-- Christiaan Pauw Nova Institute www.nova.org.za
You've been given a workable solution already, but here's a one-liner:> x <- c('sta_+1+0_field2ndtry_0000$01.cfg' , 'sta_+B+0_field2ndtry_0000$01.cfg' , 'sta_+1+0_field2ndtry_0000$01.cfg' , 'sta_+9+0_field2ndtry_0000$01.cfg') > sapply(1:length(x), function(i)gsub("\\+(.*)\\+.", paste("\\+\\1\\+", i, sep=""), x[i]))[1] "sta_+1+1_field2ndtry_0000$01.cfg" "sta_+B+2_field2ndtry_0000$01.cfg" [3] "sta_+1+3_field2ndtry_0000$01.cfg" "sta_+9+4_field2ndtry_0000$01.cfg" Sarah, fan of regular expressions On Fri, Dec 2, 2011 at 6:30 AM, Alaios <alaios at yahoo.com> wrote:> Dear all, > I would like to search in a string for the second occurrence of a symbol and replace the symbol after it > > For example my strings look like > > sta_+1+0_field2ndtry_0000$01.cfg > > I want to find the digit that comes after the second +, in that case is zero > and then over a loop create the strings below > > sta_+1+0_field2ndtry_0000$01.cfg > > sta_+1+1_field2ndtry_0000$01.cfg > > sta_+1+2_field2ndtry_0000$01.cfg > > sta_+1+3_field2ndtry_0000$01.cfg > > and so on.. > I have already tried strsplit but this will make things more complex... > > Could you please help me with that? > > B.R > Alex >-- Sarah Goslee http://www.functionaldiversity.org