R help - Sep 2011 - Invisible doesn't exit function?

I thought that invisible works like return()
However, it appears that it doesn't exit a function.  Is it supposed to work
this way?


funInvisible = function(){
    invisible(10)
    cat('I was not expecting this to print\n')
    cat('because it occurs after the invisible return\n')
}
funInvisible()


funVisible = function(){
    cat('start of function\n')
    return(10)
    cat('This error is safely avoided: \n')
    cat(1 / 0)
}
funVisible()

	[[alternative HTML version deleted]]

On 11-09-19 5:11 PM, Gene Leynes wrote:
> I thought that invisible works like return()
> However, it appears that it doesn't exit a function.  Is it supposed to
work
> this way?
>


Yes, invisible() just marks its argument as non-printing.  You still 
need to return it.  (The man page is a little ambiguous, but what it is 
saying is that a call to invisible() returns a non-printing object.  It 
isn't saying that it triggers a return from the caller.)

Duncan Murdoch

 >
> funInvisible = function(){
>      invisible(10)
>      cat('I was not expecting this to print\n')
>      cat('because it occurs after the invisible return\n')
> }
> funInvisible()
>
>
> funVisible = function(){
>      cat('start of function\n')
>      return(10)
>      cat('This error is safely avoided: \n')
>      cat(1 / 0)
> }
> funVisible()
>
> 	[[alternative HTML version deleted]]
>
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